Answer:
i took g = 9.8m/s
A. 1.16secs
B. 2.32secs
C. 6.57m
D. 57.91m
Explanation:
A. How long does the Missile take to reach ot peak?
Time taken (t) =( U²Sin (angle) )/g
u = initial velocity = 25m/s
angle given = 30°
g = acceleration due to gravity = 9.8m/s²
t = U² x Sin (angle) / g
t = 25² x Sin(30)/9.8
t = 1.61secs
B. How long is the missile in the air in total?
T = 2t
T = 2 x 1.61 = 2.32 secs
C. what maximum Height does the missile reach?
- Maximum height = U²Sin²(angle) / 2g
- M.H =25² x Sin(30)² / 2 x 9.8
- M.H=6.57m
- Maximum height= 6.57m
D. How far does the missile travel Horizontally?
- Range = U²2Sin(angle)/g
- Range = 25² x 2 x Sin(30) / 9.8
- Range = 57.91m
Calculate the amount of time it takes to heat the water by dividing the power used to heat the water, which was determined to be 1.867 with the heater element rating, listed in kW. So if your heater element rating was 3.6 kW, your equation would look like this: heating time = 1.867 ÷ 3.6, or heating time =0.52 hours.
Answer:
Explanation:
Given
See attachment
Required
Determine PCD and CPD
First, we need to calculate CPD
Since DPA is a straight line and CPA = 100;
We have that:
--- angle on a straight theorem
Substitute 100 for CPA
Subtract 100 from both sides
Next, we calculate PCD
We have that:
--alternate angle
In triangle PCD
--- angles in a triangle
Where
So, we have:
Subtract 136 from both sides
Answer:
k = 22.05 N/m
Explanation:
The potential energy of the mass is converted into potential energy of the spring.
Given:
mass m = 0.27 kg
gravitational constant g = 9.8 m/s²
distance falling/ stretching of spring h = 0.24 m
Solving for k: