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AleksAgata [21]
3 years ago
8

I need help plissss..............

Physics
2 answers:
aalyn [17]3 years ago
8 0
Answer: A.
Have a good day!!!!
Charra [1.4K]3 years ago
7 0
The answer is A
hope this helps
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An astronaut floating in space throws a wrench forward with the force of 10 N.
Jobisdone [24]

Answer:

10N

Explanation:

1. Every Action has an equal and opposite reAction.

2. If 10N of force is acted upon an wrench, then the wrench will react with an equal amount of force, but in the opposite direction.

7 0
3 years ago
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You are in a contest with your friends to see who can drive a golf ball the farthest. should you hit a "line drive" (low to the
WITCHER [35]
Line drive would be more farthest from the very high angle shot because when we increase the angle of flight the range started to increase and at some point it becomes maximum and that angle is 45° after that as you go on increasing the angle it won't be covering more distance as compared to the max at (45°) .
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3 years ago
Which of these is an illuminated source of light? A. the sun B. a star C. the earth seen from the moon D. a meteorite as it burn
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C. the earth seen from the moon . The others are luminous objects
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3 years ago
A force of constant magnitude pushes a box up a vertical surface, as shown in the figure.
Ray Of Light [21]

The work done on the box by the applied force is zero.

The work done by the force of gravity is 75.95 J

The work done on the box by the normal force is 75.95 J.

<h3>The given parameters:</h3>
  • Mass of the box, m = 3.1 kg
  • Distance moved by the box, d = 2.5 m
  • Coefficient of friction, = 0.35
  • Inclination of the force, θ = 30⁰

<h3>What is work - done?</h3>
  • Work is said to be done when the applied force moves an object to a certain distance

The work done on the box by the applied force is calculated as;

W = Fd cos(\theta)\\\\W = (ma)d \times cos(\theta)

where;

a is the acceleration of the box

The acceleration of the box is zero since the box moved at a constant speed.

W = (0) d \times cos(30)\\\\W = 0 \ J

The work done by the force of gravity is calculated as follows;

W = mg \times d\\\\W = 3.1 \times 9.8 \times 2.5 \\\\W = 75.95 \ J

The work done on the box by the normal force is calculated as follows;

W = (F_n) \times d\\\\W = (mg + F sin\theta) \times d\\\\W = (mg + 0) \times d\\\\W = mgd\\\\W = 3.1 \times 9.8 \times 2.5\\\\W = 75.95 \ J

Learn more about work done here: brainly.com/question/8119756

8 0
2 years ago
A uniform solid ball rolls smoothly along a floor, then up a ramp inclined at 33.0°. It momentarily stops when it has rolled 1.7
galben [10]

Answer:

v = 3.6 m/s

Explanation:

given,

Inclination of the ramp, θ = 33⁰

Distance of the rope, d = 1.70 m

initial speed = ?

using conservation of energy

\dfrac{1}{2}mv^2 + \dfrac{1}{2}I_{com}\omega^2 = m g h

h = d sinθ  

h = 1.7 x sin 33° = 0.926 m

moment of inertia of the solid ball

I_{com}= \dfrac{2}{5}MR^2  

we know, v = r ω

\dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{2}{5}mR^2\times \dfrac{v^2}{R^2}= m g h

\dfrac{1}{2}mv^2 + \dfrac{1}{5}mv^2 = mgh

gh= \dfrac{7}{10}v^2

v = \sqrt{\dfrac{10}{7}gh}

v = \sqrt{\dfrac{10}{7}\times 9.8\times 0.926}

v = 3.6 m/s

Hence, initial speed of the solid ball = 3.6 m/s

8 0
3 years ago
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