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3 years ago

I need help plissss..............

Physics

2 answers:

aalyn [17]3 years ago

8 0

Answer: A.
Have a good day!!!!

Charra [1.4K]3 years ago

7 0

The answer is A
hope this helps

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) The magnitude of scalar product of two unit vectors perpendicular to each other is

fenix001 [56]

This question involves the concept of the scalar product.

The magnitude of the scalar product will be "0".

<h3>SCALAR PRODUCT</h3>

The scalar product, also known as the dot product of the two vectors is given by the following formula:

$A.B = |A||B|Cos\theta$

where,

A.B = Scalar product = ?
|A| = Mangnitude of vector A = 1 unit
|B| = Magnitude of Vector B = 1 unit
θ = Angle between vectors = 90°

Therefore,

$A.B = (1)(1)Cos90^o = (1)(1)(0)$

A.B = 0

Learn more about scalar product here:

brainly.com/question/6849226

5 0

3 years ago

A spherical raindrop 2.5 mm in diameter falls through a vertical distance of 3900 m. Take the cross-sectional area of a raindrop

Karolina [17]

Answer:

276.62 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)

Equation of motion

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 3900+0^2}\\\Rightarrow v=276.62\ m/s$

<u>Neglecting air drag</u> the velocity of the spherical drop would be 276.62 m/s

5 0

3 years ago

A manganese atom is pictured below.

Rufina [12.5K]

Manganese has 2 (two) electron that would free floating and able to form a metallic bond.
The electronic configuration of manganese is (Ar) 3d5 4s2. The two electron in 4s orbital are the valence electron which can freely move from one place to another.

5 0

3 years ago

Read 2 more answers

Two water balloons of mass 0.75 kg collide and bounce off of each other without breaking. Before the collision, one water balloo

bagirrra123 [75]

By the law of momentum conservation:-
=>m¹u¹ + m²u² = m1v1 + m²v² {let East is +ve}
=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
<span> =>v¹ = 2.25 m/s (East) </span>

5 0

3 years ago

The drag force that resists the motion of a car traveling at 80 km h^- 1 is 300 N.

kobusy [5.1K]

The power require to keep the car traveling is 6,666 W.

The power of the engine at the given efficiency is 3,999.6 W.

<h3>What is Instantaneous power?</h3>

This the product of force and velocity of the given object.

The power require to keep the car traveling is calculated as follows;

P = Fv

$P = 300\ N \ \times \ \frac{80 \ kmh^{-1}}{3.6 \ km h^{-1}/m/s} \\\\
P = 300 \ N \times 22.22 \ m/s\\\\
P = 6,666 \ W$

The power of the engine at the given efficiency is calculated as follows;

$E = \frac{P_{out}}{P _{in}} \times 100\%\\\\
60\% = \frac{P_{out}}{6,666} \times 100\%\\\\
0.6 = \frac{P_{out}}{6,666} \\\\
P_{out} = 3,999.6 \ W$

Learn more about efficiency here: brainly.com/question/15418098

8 0

2 years ago