Answer:
C(s) + H2O(g) → CO(g) + H2(g)
Explanation:
Carbon monoxide and hydrogen. Possibly some reaction products from impurities in the coke, but mostly CO and H2.
First let us calculate for the rate constant k from the
formula:
k = ln(2) / t0.5
where t0.5 is the half life
k = ln(2) / 1.3x10^9 years
k = 5.33x10^-10 years-1
Then we use the formula:
A/Ao = e^-kt
where A/Ao is the amount remaining = 25% = 0.25, t is
time
Rearranging to get t:
t = ln(A/Ao) / -k
t = ln(0.25) / (-5.33x10^-10 years-1)
t = 2.6x10^9 years
The Euglena is an example of a micro-organism.
Answer: 225 joules.
Explanation:
If this a one dimension problem, this is the motion is in the same direction of the force, the equation for work is:
Work = distance × force
⇒ Work = 15 m × 15 N = 225 joules.
This is a special case of the general equation
Work = |F| |displacement| cosine (angle between the force and displacement)
When force and displacement are in the same direction, the angle is 0, so cos(0) = 1. This is the two vectors are parellel and the work is just the product of the two magnitudes (force and distance)
Answer:
The frequency of radiation is 1.25 × 10¹⁵ Hz.
Explanation:
Given data:
Wavelength = 2.40 x 10^-5 cm or 2.4 x 10^-7 m
frequency = ?
Solution:
Formula:
f = c / λ
f = frequency
c = speed of light (3×10⁸ m/s)
λ = Wavelength
Now we will put the values in formula
f = c / λ
f = 3×10⁸ m/s /2.40 x 10⁻⁷m
f = 1.25 × 10¹⁵ s⁻¹
or
f = 1.25 × 10¹⁵ Hz (s⁻¹ = Hz)