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3 years ago

Need help ASAP please!

Chemistry

1 answer:

bearhunter [10]3 years ago

3 0

Answer:

13 mol NO

Explanation:

Step 1: Write the balanced equation

4 NH₃(g) + 5 O₂(g) ⇒ 4 NO(g) + 6 H₂O(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to NO is 5:4.

Step 3: Calculate the number of moles of O₂ needed to produce 16 moles of NO

We will use the previously established molar ratio.

16 mol O₂ × 4 mol NO/5 mol O₂ = 13 mol NO

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What is the mass of a block with a volume of 18 cm^3, and a density of 9.2 g/cm^3?

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Answer: 165.6grams

Explanation:

Mass of a block = ?

Volume of block = 18 cm^3

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3 years ago

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Cl⁻

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3 years ago

A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema

timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T}=k$

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case:

V1= 5.76 L
T1= 22 °C= 295 °K (Being 0°C=273°K)
V2=17.28 L
T2=?

Replacing:

$\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}$

Solving:

$T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}$

T2= 885 °K = 612 °C

The final temperature was 612 °C

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2 years ago