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Pie
3 years ago
11

Need help ASAP please!

Chemistry
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

13 mol NO

Explanation:

Step 1: Write the balanced equation

4 NH₃(g) + 5 O₂(g) ⇒ 4 NO(g) + 6 H₂O(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of O₂ to NO is 5:4.

Step 3: Calculate the number of moles of O₂ needed to produce 16 moles of NO

We will use the previously established molar ratio.

16 mol O₂ × 4 mol NO/5 mol O₂ = 13 mol NO

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Ganezh [65]

Answer:

The potential energy the apple had due to its height is converted to kinetic energy

Explanation:

When an apple falls from the tree to the ground, its <u>energy of position stored as gravitational potential energy is converted to kinetic energy</u>, the energy of motion, as it falls. When the apple hits the ground, kinetic energy is transformed into heat energy.

7 0
3 years ago
Solids and liquids have both mass and volume, but a gas has only mass.<br> a. True<br> b. False
tino4ka555 [31]
True. A gas does not have a definite volume. Therefore, making this statement correct. <span />
6 0
3 years ago
Pls help! It takes 1 molecule of nitrogen and 3 molecules of hydrogen to produce 2 molecules of ammonia using the following form
mariarad [96]

Answer:

The correct answer is option ( D )

5 0
3 years ago
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.
klio [65]

Answer:

Mass of CaCl₂ produced = 15 g

Excess reactant = CaCO₃

Mass of CaCO₃ left = 11.5 g

Explanation:

Given data:

Mass of calcium carbonate = 25 g

Mass of hydrochloric acid = 10.0 g

Mass of calcium chloride produced = ?

Chemical equation:

CaCO₃ + 2HCl  → CaCl₂  + H₂O + CO₂

Number of moles of CaCO₃:

Number of moles of CaCO₃ = Mass /molar mass

Number of moles of CaCO₃= 25.0 g / 100.1 g/mol

Number of moles of CaCO₃ = 0.25 mol

Number of moles of HCl:  

Number of moles of HCl = Mass /molar mass

Number of moles of HCl = 10.0 g / 36.5 g/mol

Number of moles of HCl = 0.27 mol

Now we will compare the moles of CaCl₂ with HCl and CaCO₃ .

                  CaCO₃      :               CaCl₂

                   1               :               1

                 0.25           :            0.25

                HCl              :                CaCl₂

                 2                :                 1

                 0.27            :               1/2 × 0.27 = 0.135 mol

The number of moles of CaCl₂ produced by HCl are less it will be limiting reactant.

Mass of CaCl₂ = moles × molar mass

Mass of CaCl₂ =0.135 mol × 110.98 g/mol

Mass of CaCl₂ =  15 g

The calcium carbonate is present in excess.

               HCl              :                CaCO₃

                 2                :                 1

                 0.27            :               1/2 × 0.27 = 0.135 mol

So, 0.135 moles react with 0.27 moles of HCl.

The moles of CaCO₃ remain unreacted = 0.25 - 0.135

The moles of CaCO₃ remain unreacted = 0.115 mol

Mass remain unreacted:

Mass of of CaCO₃ remain unreacted = Moles × molar mass

Mass of of CaCO₃ remain unreacted = 0.115 mol × 100.1 g/mol

Mass of of CaCO₃ remain unreacted = 11.5 g

7 0
4 years ago
An open flask sitting in a lab fridge looks empty, but it is filled with a mixture of gases called air. Calculate the number of
KATRIN_1 [288]

Answer: The number of molecules of gas the flask contains is 0.674\times 10^{23}

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm   (STP)

V = Volume of gas = 2.50 L

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature = 273K (STP)

n=\frac{PV}{RT}

n=\frac{1atm\times 2.50L}{0.0821 L atm/K mol\times 273K}=0.112moles

According to Avogadro's law:

1 mole of gas at STP contains =6.023\times 10^{23} molecules

Thus 0.112moles of gas at STP contains = \frac{6.023\times 10^{23}}{1}\times 0.112=0.674\times 10^{23} molecules

The number of molecules of gas the flask contains is 0.674\times 10^{23}

7 0
3 years ago
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