Question

If you have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, which element is the reactant in excess? 3H2 + N2 → 2NH3

Answer 1

Answer:

nitrogen

Explanation:

The stoichiometry of the reaction says that $H_{2}$ and  $N_{2}$ react 3:1 to form 2 moles of  $NH_{3}$, so, if you have 3,5 moles of H, which is equal to 1,75 moles of  $H_{2}$, and 5 moles of N, which are equal to 2,5 moles of  $n_{2}$. only$\frac{1,75 moles of H2}{3}$=0.583 moles of  $N_{2}$, will react, leaving 1.917 moles of $N_{2}$ unreacted, and forming 0.583*2=1.166 moles of  $NH_{3}$