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3 years ago

9

PLZ HELP Which factors play a role in creating ocean waves?

2 answers:

Irina18 [472]3 years ago

5 0

Answer:

<em>Hello, The factors that play a role in creating ocean waves are the wind speed, direction, duration, and fetch. Ocean waves are usually produced by the wind that moves its energy to the water. The size of the wave can be determined by the wind speed, direction, duration, and fetch (area in which the wind blows). This changeability resulted in waves of different sizes and shapes. So, The answer is B. Hope That Helps!</em>

Yuki888 [10]3 years ago

4 0

Answer:

all of these

Explanation:

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Please someone answer this for me ASAP

Alex777 [14]

Answer:

I'm not 100% sure but I think it is b I'm not great with math tho

6 0

3 years ago

Which of the following solutions will behave closest to an ideal solution?

puteri [66]

The science part because the science is particularly of science

6 0

3 years ago

How would the addition of protons affect the concentration of CH3COOH? How would the addition of OH– affect the amount of CH3COO

Deffense [45]

Answer:

1) increase concentration

2) decrease the amount

3) decrease the concentration

4) it would increase

Explanation: edge 2021

8 0

3 years ago

Read 2 more answers

5. A box with a volume of 22.4 L contains 1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C. Which of the following statements

love history [14]

B. The partial pressure of N2 is 101 kPa

<h3>Further explanation</h3>

Given

volume = 22.4 L

1.0 mol of nitrogen and 2.0 mol of hydrogen at 0°C

Required

Total pressure and partial pressure

Solution

Ideal gas law :

PV = nRT

n total = 3 mol

T = O °C + 273 = 273 K

P = nRT/V

P = 3 x 0.08205 x 273 / 22.4

P total = 3 atm = 303,975 kPa

P Nitrogen = 1/3 x 303.975 = 101.325 kPa

P Hydrogen = 2/3 x 303.975 = 202.65 kPa

7 0

3 years ago

Determine the equilibrium constant, Kp, for the following reaction, by using the two reference equations below: 2 NO(g) + O2(g)

klio [65]

Answer:

$Kp=3.07x10^6$

Explanation:

Hello,

In this case, by knowing the given reference reactions, one could rearrange them as follows:

$2 NO(g) \leftrightarrow N_2(g) + O_2(g); Kp_2 = \frac{1}{2.3 x 10^{-19}}=4.35x10^{18}$

$N_2(g) + 2O_2(g) \leftrightarrow 2NO_2(g);Kp_3=(8.4x10^{-7})^2=7.056x10^{-13}$

Subsequently, to obtain the main reaction, we add the aforementioned reference rearranged reactions as shown below (just as reference):

$2NO(g)+N_2(g)+2O_2\leftrightarrow 2NO_2(g)+N_2+O_2$

Consequently, the equilibrium constant is computed as:

$Kp=\frac{[N_2][O_2]}{[NO]^2} * \frac{[NO_2]^2}{[N_2][O_2]^2} =Kp_2*Kp_3=4.35x10^{18}*7.056x10^{-13}=3.07x10^6$

Best regards.

8 0

3 years ago