Answer:
Amount of heat required = 153.62 J
Explanation:
Given:
Mass = 163.45 g
∆Hvap = 43.3 kJ/mol
Molar mass C₂H₅OH = 46.07 g/mol
Find:
Amount of heat required
Computation:
Amount of heat required = Number of moles x Molar mass C₂H₅OH
Amount of heat required = [163.45/46.07][43.3]
Amount of heat required = 153.62 J
D. 293
According to Charle’s law, with pressure being constant, an increase in volume will also increase the temperature. 10 degrees Celsius is 283 K, so you would need to find the number greater than 283 K which is 293 K.
<span>Answer: at 0.01 °C and 0.0060 atm the three phases (solid, liquid and gas)
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</span><span>Explanation:
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</span><span>1) Water at 0.0060 atm and 0.01° C is at its triple point.
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2) The triple point is the point in the phase diagram at which the three physical states coexist: gas, liquid and solid.
3) That means that water can freeze and boil at the same time. In fact they can happen any of the six changes of phase: freezing (liquid to solid), melting (solid to liquid), evaporation (liquid to gas), condensation (gas to liquid), sublimation (solid to gas), and deposition (gas to solid).
The phase diagram is unique for any substance, meaning that it is different for different substances: the normal boiling and melting points are different.
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Explanation:
AgNO₃+Na₃(PO₄) → Ag₃(PO₄) + NaNO₃
To balance this chemical equation, we can adopt a simple mathematical approach through which we can establish simple and solvable algebraic equations.
aAgNO₃ + bNa₃PO₄ → cAg₃PO₄ + dNaNO₃
a, b, c and d are the coefficients needed to balance the equation.
Conserving Ag: a = 3c
N: a = d
O: 2a + 4b = 4c + 2d
Na: 3b = d
P: b = c
let a = 1; d = 1
b = 
c =
Multiplying through by 3:
a = 3, b = 1, c = 1 and d = 3
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Learn more:
Balanced equation
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