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bezimeni [28]
3 years ago
7

HELP ASAP 2 MORE MINUTES ON TEST!!!!!!!!!!! PLEASE YALL HELP!

Mathematics
2 answers:
lilavasa [31]3 years ago
7 0

Answer:

The enlarged length would be 60 in

The enlarged width would be 35in

Step-by-step explanation:

The enlarged length would be 12*5 = 60

The enlarged width would be 7*5 = 35

Hope this helps!!

- Kay

Damm [24]3 years ago
6 0

Answer:

Length=60in

Width= 35 in

Step-by-step explanation:

Don’t forget the unit

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Mr. Smith has 15.6 pounds of oranges to pack for shipment. He can ship 2.4 pounds of oranges in a large box and 1.2 pounds in a
s2008m [1.1K]

Answer:

3 boxes.

Step-by-step explanation:

Let x represent number of 1.2 pounds boxes.

We have been given that Mr. Smith has 15.6 pounds of oranges to pack for shipment. He can ship 2.4 pounds of oranges in a large box and 1.2 pounds in a small box.

The oranges covered in x small boxes would be 1.2x    

Oranges packed in 5 large boxes would be 5\times 2.4\text{ pounds}=12\text{ pounds}.

We can represent our given information in an equation as:

1.2x+12=15.6  

1.2x+12-12=15.6-12  

1.2x=3.6  

\frac{1.2x}{1.2}=\frac{3.6}{1.2}  

x=3  

Therefore, the minimum number of small boxes required to ship the rest of the oranges would be 3 boxes.

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3 years ago
This circle graph shows the results of a survey that asked 80 people which method of transportation they use to get to the city
raketka [301]

Answer:

Step-by-step explanation:

Where the graph at??

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I need help to grab a line this is a stadi G checkpoint it gives you the answer if you do not know it but I don’t want just the
olga55 [171]

The most direct form to graph a line, is to find two points of it and connect them with a line.

Here we have:

y=2x-6

Let's find the point where x = 0. To do this, we replace the x in the equation by 0:

\begin{gathered} y=2\cdot0-6 \\ y=-6 \end{gathered}

We have our first point: (0, -6)

Next let's find the point where y = 0. Again, we replace y in by 0 in the equation:

\begin{gathered} 0=2x-6 \\ 6=2x \\ x=\frac{6}{2}=3 \end{gathered}

We have our second point, (3, 0)

Now all we have to do is plot the points (0, -6) and (3, 0) in the plane, and connect them with a line, and then the line is graphed

The line should look like this:

8 0
1 year ago
In a survey of 100 Phoenix high school students, 43 were male students. 42 students were female and went to Phoenix Full time. I
Elanso [62]
30 male students do full time.
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3 years ago
PLEASE HELP ME!<br> Drag the expressions into the boxes to correctly complete the table.
Kamila [148]

<em><u>The polynomials are:</u></em>

x^4+3x^3-5x^2-7x+20

x^3-2x^2+x-12

x^2+3x^5-6x+12x^3

<em><u>Not a polynomial are:</u></em>

4\sqrt[3]{x} -\sqrt{x}  -20

\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40

x^{-3}-x^{-2}-6x^{-1}+8

<em><u>Solution:</u></em>

Polynomial is an expression with variables and coefficients,

Which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables

<em><u>Option 1</u></em>

4\sqrt[3]{x} -\sqrt{x}  -20

Polynomial does not include roots

This is not a polynomial equation

<em><u>Option 2</u></em>

x^4+3x^3-5x^2-7x+20

This is polynomial expression involving addition and subtraction between terms with non-negative integer exponents of variables

<em><u>Option 3</u></em>

\frac{5}{x^3}-\frac{1}{x^2}+\frac{8}{x}-40

This is not a polynomial. This equations involves negative integer exponents of variables

<em><u>Option 4</u></em>

x^3-2x^2+x-12

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

<em><u>Option 5</u></em>

x^{-3}-x^{-2}-6x^{-1}+8

This is not a polynomial. This equations involves negative integer exponents of variables

<em><u>Option 6</u></em>

x^2+3x^5-6x+12x^3

This is a polynomial involving addition and subtraction between terms with non-negative integer exponents of variables

5 0
3 years ago
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