Ask question

Ask question

All categories

3 years ago

8

A 730 N student stands in the middle of a frozen pond having a radius of 5.8 m. He is unable to get to the other side because of

a lack of friction between his shoes and the ice. To overcome this difficulty, he throws his 2.6 kg physics textbook horizontally toward the north shore at a speed of 6.1 m/s. The acceleration of gravity is 9.81 m/s². How long does it take him to reach the south shore? Answer in units.

1 answer:

dedylja [7]3 years ago

7 0

Answer:27.35 s

Explanation:

Given

weight of man =730 N

mass of man $m_1=\frac{730}{9.8}=74.48 kg$

radius of pound r=5.8 m

mass of book $m_2=2.6 kg$

velocity of book $v_2=6.1 m/s$

let $v_1$ be the velocity of man

conserving momentum

$0=m_1v_1+m_2v_2$

$0=74.48\times v_1+2.6\times 6.1$

$v_1=\frac{15.86}{74.48}=0.212 m/s$

time taken by man to reach south end

$t=\frac{5.8}{0.212}=27.35 s$

You might be interested in

g the total mechanical energy of the satellite-Earth system when the satellite is in its current orbit is E. In order for the sa

Olegator [25]

Answer:

The correct answer is " $\frac{4E}{3}$ ".

Explanation:

According to the question,

Energy of satellite,

⇒ $E_s=-\frac{GM_sM_E}{2r}$

For the very 1st case:

$r = R_E+R_E$

$=2R_E$

or,

⇒ $E=-\frac{GM_sM_E}{4R_E}$ ...(1)

For the new case:

$r = R_E+\frac{R_E}{2}$

$=\frac{3R_E}{2}$

then,

⇒ $E'=-\frac{GM_sM_E}{2 \frac{3R_E}{2} }$

$=-\frac{GM_sM_E}{3R_E}$ ...(2)

From equation (1) and (2), we get

⇒ $E'=\frac{1}{3}(4E)$

$=\frac{4E}{3}$

7 0

3 years ago

Which part of a feedback mechanism is able to monitor the conditions outside of cells and usually uses nerve cells to relay this

Agata [3.3K]

Answer: A.) sensor

Explanation:

Homeostasis is the ability of the organism's inner body to regulate the internal environment in stable state with respect to the changes occurring in the external environment. It is usually done by the feedback controls.

The maintenance of homeostasis within the body is essential. The following are the factors which controls the homeostasis. These includes:

1. Stimulus: It generate a response. It is an external factor which brings change in the internal body of the organism.

2. Receptor/ sensor: It detects the external stimulus and responds to the change.

3. Control center: The information from the receptor travels along the afferent pathway towards the control center. The function of the control center is to determine the response and controls the action.

4. Effector: The information from the control center travels down the efferent pathway to the effector. The function of the effector is to balance the stimulus to regulate and maintain homeostasis.

5 0

3 years ago

A ball is rolling across the floor at a constant velocity. What is the value of the change in its kinetic energy, ΔEk?

Katyanochek1 [597]

B. When the ball is rolling across the floor at a constant velocity, the change in its kinetic energy is zero.

<h3>What is change in kinetic energy?</h3>

The change in kinetic energy of an object is the dereference between the final kinetic energy and the initial kinetic energy.

ΔK.E = K.Ef - K.Ei

ΔK.E = 0.5m(vf² - vi²)

where;

K.Ef is the final kinetic energy
K.Ei is the initial kinetic energy
vf is final velocity
vi is initial velocity

At constant velocity, the initial velocity and final velocity are equal.

ΔK.E = 0.5m(0) = 0

Thus, when the ball is rolling across the floor at a constant velocity, the change in its kinetic energy is zero.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

5 0

2 years ago

Why a male who has undergone a vasectomy would be unable to impregnate a female

irina [24]

A vasectomy disables a man in making sperm so therefore would not be able to impregnate I woman

6 0

3 years ago

Read 2 more answers

Two identical objects A and B fall from rest from different heights to the ground. If object B takes twice as long as object A t

Yuki888 [10]

Answer:

1:4

Explanation:

We have, two identical objects A and B fall from rest from different heights to the ground.

Object B takes twice as long as object A to reach the ground. It is required to find the ratio of the heights from which A and B fell. Let $h_A\ \text{and}\ h_B$ are the height for A and B respectively. So,

$\dfrac{h_A}{h_B}=\dfrac{(1/2)gt_A^2}{(1/2)gt_B^2}\\\\\dfrac{h_A}{h_B}=\dfrac{t_A^2}{t_B^2}$

We have,

$t_B=2t_A$

So,

$\dfrac{h_A}{h_B}=\dfrac{t_A^2}{(2t_B)^2}\\\\\dfrac{h_A}{h_B}=\dfrac{1}{4}$

So, the ratio of the heights from which A and B fell is 1:4.

7 0

3 years ago