This is a problem that can be solved using free-fall motion analysis. Since the displacement (2.9m) is given, we can use the following equation to solve for the impact speed:
V^2 = 2gh
V = sqrt (2*9.8*2.9)
V = 7.54 m/s
The jigsaw can be used to make both straight and curved cuts in a wide variety of materials, including wood, particleboard, plywood, plastic, metal, even ceramic tile. There is also way more than those, but those are just the basics or common things. Hope this helps!
Answer:
a) 4.65m/s
b) 59.8 N , 1.01125 N
Explanation:
a)
m = mass of the ball = 1 kg
r = length of the string = 2.0 m
h = height gained by the ball as it moves from lowest to topmost position = 2r = 2 x 2 = 4 m
v = speed at the lowest position = 10 m/s
v' = speed at the topmost position = ?
Using conservation of energy
Kinetic energy at topmost position + Potential energy at topmost position = Kinetic energy at lowest position
(0.5) m v'² + m g h = (0.5) m v²
(0.5) v'² + g h = (0.5) v²
(0.5) v'² + (9.8 x 4) = (0.5) (10)²
v' = 4.65m/s
b)
T' = Tension force in the string when the ball is at topmost position
T = Tension force in the string when the ball is at lowest position
At the topmost position:
force equation is given as
T' = 1.01125 N
At the lowest position:
force equation is given as
T = 59.8 N
Answer:
θ = 1.591 10⁻² rad
Explanation:
For this exercise we must suppose a criterion when two light sources are considered separated, we use the most common criterion the Rayleigh criterion that establishes that two light sources are separated census the central maximum of one of them coincides with the first minimum of the other source
Let's write the diffraction equation for a slit
a sin θ = m λ
The first minimum occurs for m = 1, also field in these we experience the angles are very small, we can approximate the sin θ = θ
θ = λ / a
In our case, the pupil is circular, so the system must be solved in polar coordinates, so a numerical constant is introduced.
θ = 1.22 λ / D
Where D is the diameter of the pupil
Let's apply this equation to our case
θ = 1.22 600 10⁻⁹ / 0.460 10⁻²
θ = 1.591 10⁻² rad
This is the angle separation to solve the two light sources
