1. The time taken for the car to reach a velocity of 60 m/s is 8.57 s
2. The distance travelled during the time is 257.14 m
<h3>What is acceleration? </h3>
The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
- a is the acceleration
- v is the final velocity
- u is the initial velocity
- t is the time
1. How to determine the time
- Initial velocity (u) = 0 m/s
- Acceleration (a) = 7 m/s²
- Final velocity (v) = 60 m/s
- Time (t) =?
a = (v – u) / t
Thus,
t = (v – u) / a
t = (60 – 0) / 7
t = 8.57 s
2. How to determine the distance
- Initial velocity (u) = 0 m/s
- Acceleration (a) = 7 m/s²
- Final velocity (v) = 60 m/s
- Distance (s) = ?
v² = u² + 2as
60² = 0² + (2 × 7 × s)
3600 = 0 + 14s
3600 = 14s
Divide both sides by 14
s = 3600 / 14
s = 257.14 m
Learn more about acceleration and velocity:
brainly.com/question/491732
brainly.com/question/19466392
#SPJ1
Answer:
The fraction of kinetic energy lost in the collision in term of the initial energy is 0.49.
Explanation:
As the final and initial velocities are known it is possible then the kinetic energy is possible to calculate for each instant.
By definition, the kinetic energy is:
k = 0.5*mV^2
Expressing the initial and final kinetic energy for cars A and B:


Since the masses are equals:

For the known velocities, the kinetics energies result:




The lost energy in the collision is the difference between the initial and final kinectic energies:


Finally the relation between the lost and the initial kinetic energy:


HCl + NaOH -> H2O + NaCl
CaCO3 + KI -> K2CO2 + CaI2
AlF3 + Mg(NO3)2 -> Al(NO3)3 + MgF2
Well mostly because it's for oceans and lakes that have waves. so if you don't live near any of these, you wouldn't be getting power. <span />