Answer:
The stretched length is 0.18816 in.
Explanation:
Given that,
Distance = 0.5 in
length = 8 ft
Tensile stress = 20 kpsi
We need to calculate the stretched length
Using formula of length
![\Delta L=\dfrac{PL}{AE}](https://tex.z-dn.net/?f=%5CDelta%20L%3D%5Cdfrac%7BPL%7D%7BAE%7D)
![\Delta L=\sigma\times\dfrac{L}{E}](https://tex.z-dn.net/?f=%5CDelta%20L%3D%5Csigma%5Ctimes%5Cdfrac%7BL%7D%7BE%7D)
Where,
= Tensile stress
L = length
E = young's modulus of aluminum
Put the value into the formula
![\Delta L= 20\times10^3\dfrac{8}{10.2\times10^{6}}](https://tex.z-dn.net/?f=%5CDelta%20L%3D%2020%5Ctimes10%5E3%5Cdfrac%7B8%7D%7B10.2%5Ctimes10%5E%7B6%7D%7D)
![\Delta L= 0.01568\ ft](https://tex.z-dn.net/?f=%5CDelta%20L%3D%200.01568%5C%20ft)
![\Delta L=0.01568\times12](https://tex.z-dn.net/?f=%5CDelta%20L%3D0.01568%5Ctimes12)
![\Delta L=0.18816\ in](https://tex.z-dn.net/?f=%5CDelta%20L%3D0.18816%5C%20in)
Hence, The stretched length is 0.18816 in.
<span>The loudness of the sound increases gradually as the air is slowly introduced in to the jar. This is because sound needs a physical medium and in a vacuum there is none. The air provides that medium and as it is introduced, the transfer of sound energy increases</span>
Answer:
The answer is C "think about the problem first, systematically consider all factors, and form a hypothesis"
Explanation:
In physics there is some basic fomula that sir Isacc Newton proposed under the topic of motion. The three formulas are below;
<em>1) v=u+at</em>
<em>2)v^2=u^2+2as</em>
<em>3)s=ut+(1/2)(at^2)</em>
the variables are explained below;
u= initial velocity of the body
a=acceleration/Speed of the body
t= time taken by the body while travelling
s= displacement of the body.
Therefore to solve keatons problem, the factors(variables) in the formulas above need to be systematically considered. Since the ball was dropped from the top of the building, the initial velocity is 0 because the body was at rest. Also the acceleration will be acceleration due to gravity (9.8m/s^2)