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solong [7]
3 years ago
13

Aless-intense wave will have fewer than a more-intense wave.

Physics
1 answer:
puteri [66]3 years ago
6 0

Decibels

Explanation:

A less intense wave will have fewer decibels than a more intense wave.

The decibel is the unit of measuring the intensity of sound waves.

The intensity of sound wave is the power carried by sound waves in a unit area.

  • Loudness is intimately related to decibels.
  • Loudness is the intensity of sound in the hearing range.

learn more:

Amplitude of sound wave brainly.com/question/2845448

#learnwithBrainly

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Answer:

(a) 0.345 T

(b) 0.389 T

Solution:

As per the question:

Hall emf, V_{Hall} = 20\ mV = 0.02\ V

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Hall emf, V'_{Hall} = 69\ mV = 0.069\ V

Now,

Drift velocity, v_{d} = \frac{V_{Hall}}{B}

v_{d} = \frac{0.02}{0.10} = 0.2\ m/s

Now, the expression for the electric field is given by:

E_{Hall} = Bv_{d}sin\theta                            (1)

And

E_{Hall} = V_{Hall}d

Thus eqn (1) becomes

V_{Hall}d = dBv_{d}sin\theta

where

d = distance

B = \frac{V_{Hall}}{v_{d}sin\theta}                      (2)

(a) When \theta = 90^{\circ}

B = \frac{0.069}{0.2\times sin90} = 0.345\ T

(b) When \theta = 60^{\circ}

B = \frac{0.069}{0.2\times sin60} = 0.398\ T

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2 years ago
The three basic economic questions societies face are (1) what goods and services to produce, (2) how to produce those goods and
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For whom should we produce it?

Explanation:

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Well,
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