What are the domain and range of the function on the<br> graph?

Find BC round to the nearest tenth

slega [8]

Answer:

6.7

Step-by-step explanation:

Here, we can apply cosine law, $c^2=a^2+b^2-2abcos\theta$

We the plug in values: $(CB)^2+6^2+5^2-2*6*5*cos74$

and solve that CB is around 6.7

3 0

3 years ago

Test scores are normally distributed with a mean of 500. Convert the given score to a z-score, using the given standard deviatio

Bond [772]

Answer:

The percentage of students who scored below 620 is 93.32%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 500, \sigma = 80$

Percentage of students who scored below 620:

This is the pvalue of Z when X = 620. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{620 - 500}{80}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

The percentage of students who scored below 620 is 93.32%.

3 0

3 years ago

Read 2 more answers

Jack is using a ladder to hang lights up in his house.he places the ladder 5 feet from the base of his house and leans it so it

Mariana [72]

B I’m not very good at math buh I’m sure that’s the answer

5 0

3 years ago

Read 2 more answers

The graph shows the distribution of the number of text messages young adults send per day. The distribution is approximately Nor

erik [133]

The percentage of young adults send between 128 and 158 text messages per day is; 34%

<h3>How to find the percentage from z-score?</h3>

The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.

We are given;

Sample mean; x' = 158

Population mean; μ = 128

standard deviation; σ = 30

We want to find the area under the curve from x = 248 to x = 158.

where x is the number of text messages sent per day.

To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;

z = (x - μ)/σ

z = (158 - 128)/30

z = 30/30

z = 1

This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.

From online p-value from z-score calculator, we have;

P-value = 0.34134 = 34%

Approximately 34% of the the population sends between 128 and 158 text messages per day.

Read more about p-value from z-score at; brainly.com/question/25638875

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4 0

2 years ago

Evaluate: n + 8² if n = 2

Papessa [141]

Answer:

It would be 66

Step-by-step explanation:

6 0

3 years ago

What are the domain and range of the function on the graph?