This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
-2*3
Step-by-step explanation:
If she had to refund $2 for each cup (-2) and she refunded 3 cups (3) she would lose a balance of -2*3.
Answer:
the approximate value of the square root of 8 is 2.828
Answer:
What is the sequence? The sequence is +4
Step-by-step explanation:
I don't know if you are asking for the ninth or tenth term of the sequence, but I'll just list them all.
-1, 3, 7, 11, 15, 19, 23, 27, 31, 35, ...
|___||___||___||____||___||____||____||____||____|
+4 +4 +4 +4 +4 +4 +4 +4 +4
So 31 and 35 are your answer!
I hope this helps!
<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
Answer: 38
Step-by-step explanation:
3.8=19/5
u have to flip the reciprocal to divide by fraction so 1/10 will be just 10
Then u get 19/5 x 10
You can reduce the GCF so it would be 19 x 2
19 x 2 = 38
Or you can plug it into your calculator (3.8 x .1)
