Answer:
3 11/16 pounds
Step-by-step explanation:
Lynne bought a bag of grapefruit, 1 5/8 pounds of apples, and 2 3/16 pounds of bananas. The total weight of her purchases was 7 1/2 pounds. How much did the bag of grapefruit weigh?'
The Total weight = Weight of grape fruits + Weight of Apples + Weight of Bananas
Let the weight of the grape fruit = x
7 1/2 = x + 1 5/8 + 2 3/16
x = 7 1/2 - (1 5/8 + 2 3/16)
Lowest Common Denominator = 16
x= 7 1/2 - 3 + ( 10+ 3/16)
x = 7 1/2 - 3 + (13/16)
x = 7 1/2 - 3 13/16
Lowest Common Denominator = 16
x= 4 (8 - 13/16)
x = 4 (-5/16)
x = 3 11/16 pounds
Therefore, the bag of grapefruits weighed 3 11/16 pounds
30(-2/5)²(5/8) = 30*(4/25)*(5/8) = 30*4/(5*8) = 3
Answer:
OF
Step-by-step explanation:
Since the arcs are congruent, the lines intercepting them are congruent, and you will get 2 congruent right triangles. So OA is congruent to OF by CPCTC.
Answer:
Step-by-step explanation:
Since the divisor of 
is in the form of 
use what is called Synthetic Division. Remember, in this formula, −c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
−1| 2 1 0 1
↓ −2 1 −1
__________
2 −1 1 0 → 
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [2x³ + x² + 1]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than the leading coefficient of your dividend, so that 2 in your quotient can be a 2x², the −x follows right behind it, and bringing up the rear, 1, giving you the quotient of 2x² - x + 1.
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Answer:
Step-by-step explanation:
Your "y=2xsquared-12x+10" translates into y = 2x^2 - 12x + 10. This factors into y = 2(x^2 - 6x + 5).
Setting this = to 0 results in y = 2(x - 5)(x - 1) = 0, so that the x-intercepts are (5, 0) and (1, 0). The x-coordinate of the vertex lies halfway between x = 1 and x = 5, that is, at x = 3. Using synthetic division to evaluate y = 2x^2 - 12x + 10 at x = 3, we get
3 2 -12 10
6 -18
------------------
2 -6 -8
Therefore, the vertex is located at (3, -8).
Setting x = 0 results in the y-intercept: y = 2(0)^2 - 12(0) + 10 => (0, 10)
