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xeze [42]
2 years ago
8

Find g(1) if g(x) =x^2+1​A.4B.2C.3

Mathematics
2 answers:
kodGreya [7K]2 years ago
8 0

Answer:

B.2

Step-by-step explanation:

g(1) if g(x) =x^2+1

= x^2 + 1 = (1)^2 + 1 = 1 + 1 = 2

sveticcg [70]2 years ago
6 0

Answer:

B

Step-by-step explanation:

To evaluate g(1) , substitute x = 1 into g(x), that is

g(1) = 1² + 1 = 1 + 1 = 2

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3q+4+9=-14 <br> what is Q
BlackZzzverrR [31]

Hi! Your answer is q = -9

Please see an explanation for a better and clear understanding to your problem.

Any questions about my answer and explanation can be asked through comments! :)

Step-by-step explanation:

Since we want to solve for q-term. That means we are going to isolate q-term.

\huge{3q+4+9=-14}

We can add 4 and 9 together.

\huge{3q+13=-14}

Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.

\huge{3q+13-13=-14-13}\\\huge{3q=-27}

We are reaching to the final step where we divide the whole equation by 3.

\huge{\frac{3q}{3}=-\frac{27}{3}}\\\huge{q=-9}

Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!

To check the answer, simply substitute q = -9 in the equation.

\huge{3q+4+9=-14}\\\huge{3(-9)+13=-14}\\\huge{-27+13=-14}\\\huge{-14=-14}

Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.

Hope this helps!

5 0
3 years ago
The seventh-grade class is building target areas for a PE activity. The bases for the game will be circular in shape. The diamet
Scilla [17]
To calculate the area it is pi*r^2

so since r = 1/2 d

2.5^2 * pi = area
or
19.625
8 0
3 years ago
Evaluate:<br> Sigma 50 over 1 (4n - 1) = [?]
iogann1982 [59]

Answer:

50 over 1 (4n - 1) = 5050

I hope I helped you^_^

7 0
3 years ago
30 POINTS<br> The question is the picture above<br> Help PLEASE <br> Giving 30 points
Papessa [141]

.73 x .05= .0365

.733333333 x .0000000555555555= .036555555555

i think this is correct hope this helps


5 0
2 years ago
Read 2 more answers
How do you do this problem?
aev [14]

f(x) = (x - 4)^2 - 1

g(x) = -(1/4) ( x - 4)^2 + 4

both the x and y values have to be the same. Start with the y values

f(x) = g(x)

(x - 4)^2 - 1 = -(1/4) (x - 4)^2 + 4 Add 1 to both sides.

(x - 4)^2 = -(1/4) (x - 4)^2 + 5 Add 1/4(x - 4)^2 to both sides.

(5/4) (x - 4)^2 = 5 Divide by 5/4 on both sides.

(x - 4)^2 = 5//(5/4)

(x - 4)^2 = (5/1)//5/4 Invert the second fraction and multiply

(x - 4)^2 = 5/1 * 4/5

(x - 4)^2 = 4 The 5s cancel

(x - 4)^2 = 4 Take the square root of both sides.

(x - 4) = +/- 2 Add 4 to each answer. Start with +2 on the right.

x - 4 + 4 = 2 + 4

x = 4 + 2 = 6

The x value that makes f(x)- g(x) = 0 is x = 6 The point is (6,3) answer.

Answer C.

================================================

You do not need this next part. It is just for completeness.

x - 4 = - 2

x = 4 -2

x = 2

What are the y values for these 2 x values?

y = (x - 4)^2 - 1

y = (6 - 4)^2 - 1

y = 4 - 1

y = 3

The point where f(x) - g(x) = 0 is (6,3) <<<<<< Answer 1

The second point is

y = (x - 4)^2 - 1

y = (2 - 4)^2 - 1

y = (-2)^2 - 1

y = 4 - 1

y = 3

The second point is (2,3). Answer 2

Note the y values are the same. You might expect that.

3 0
3 years ago
Read 2 more answers
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