1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zepler [3.9K]
3 years ago
11

A race car travels 40 m/s around a banked (45° with the horizontal) circular (radius = 0.20 km) track. What is the magnitude of

the resultant force on the 80-kg driver of this car? O a. 0.72 kN O b.0.68 kN O c. 0.64 kN O d.0.76 kN O e. 0.52 kN
Physics
1 answer:
OLEGan [10]3 years ago
7 0

Answer:

c)F_{net} = 0.640 kN

Explanation:

As we know that resultant force is the net force that is acting on the system

As per Newton's II law we know that net force is product of mass and acceleration

so we will have

F_{net} = ma

here we know

m = 80 kg

for circular motion acceleration is given as

a_c = \frac{v^2}{R}

a_c = \frac{40^2}{200} = 8 m/s^2

now we have

F_{net} = 80 \times 8

F_{net} = 640 N

F_{net} = 0.640 kN

You might be interested in
Three-fourths of the area of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. If the en
satela [25.4K]

Answer:

The fence is 5feet less.

Explanation:

We need to determine

The less amount of fence required, if the enclosure has full width and reduced length, compared to full length and reduced width.

Approach & WorkingArea of lawn = 30 × 403/4th of the area of lawn = ¾(30 × 40) = 30 * 30

 When full width will be fenced, and reduced length will be fenced.

Width = 30 feet30 * L = 30 * 30Hence, length = 30 feetLength of fence needed = 2(30 + 30) = 120 feet

When full length will be fenced, and reduced width will be fenced

Length = 40 feet40 * W = 30 * 30W = 22.5 feetLength of fence needed = 2(40 + 22.5) = 125 feet

Difference in length of fence needed = 125 – 120 = 5 feet.

4 0
3 years ago
During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ±
Alla [95]

Answer:

P = 1 (14,045 ± 0.03 )  k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

            Δ (Pₓ / Py) =?

 Let's start by finding the momentum of each vehicle

car X

        Pₓ = m vₓ

        Pₓ = 2.34 2.5

        Pₓ = 5.85 kg m

car Y

        Py = 2,561 3.2

        Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

          ΔPₓ = m Δv + v Δm

          ΔPₓ = 2.34 0.01 + 2.561 0.01

          ΔPₓ = 0.05 kg m

         ΔP_{y} = m Δv + v Δm

         ΔP_{y} = 2,561 0.01+ 3.2 0.001

         ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

          P = Pₓ / P_{y}

          ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

          ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²

          ΔP = 0.006 + 0.0026

          ΔP = 0.009 kg m

The result is

           P = 14,045 ± 0.039 = (14,045 ± 0.03 )  k gm/s

7 0
3 years ago
I need help with some graph.<br><br> Which graph shows acceleration?
matrenka [14]

Answer:

The first graph

Explanation:

Graph A shows acceleration.

4 0
2 years ago
Read 2 more answers
A museum curator moves artifacts into place on various different display surfaces. If the curator moves a 145 kg aluminum sculpt
NikAS [45]
We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
8 0
3 years ago
Read 2 more answers
The wavelength of visible light is about 5500 times longer than the wavelength of x-rays. If you represent the wavelenth of an x
Pie

Answer:

458.33 ft

Explanation:

We are given that

Wavelength of of an x- ray photon=1 in

Wavelength of of an x- ray photon==\frac{1}{12}ft

1 in=\frac{1}{12}feet

We have to find the  length of line (in feet) drawn by you to represent the wavelength of visible light.

According to question

Wavelength of visible light=5500\times \frac{1}{12} ft

Wavelength of visible light=\frac{5500}{12}ft

Wavelength of visible light=458.33 ft

Hence, the 458.33 ft line must drawn  by you to represent the wavelength of visible light.

6 0
3 years ago
Other questions:
  • A 75kg man climbs the stairs to the fifth floor of a building. A total hieght of 16m. His potential energy has increased by
    5·1 answer
  • A circular ring with area 4.45 cm2 is carrying a current of 13.5 A. The ring, initially at rest, is immersed in a region of unif
    9·1 answer
  • You have a string with a mass of 0.0133 kg. You stretch the string with a force of 8.89 N, giving it a length of 1.97 m. Then, y
    14·1 answer
  • Why do we celebrate veterans day
    12·1 answer
  • Amit has found a rock in his backyard and would like to measure its mass, volume, and density. What tools can he use to perform
    15·1 answer
  • What does Newton's second law of motion describe?
    15·2 answers
  • Name the stages of a volcano and name the three different types of volcano mountains caused by the lava buildup.
    10·2 answers
  • Select the correct answer. What happens to the molecules within a gas when the gas condenses?
    7·1 answer
  • If you want to increase the acceleration of a baseball when you throw it, what must you increase to make this happen?
    8·1 answer
  • A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. Th
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!