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vaieri [72.5K]
3 years ago
9

If two runners running a 10k race start at the same time but runner A runs at 4.39m/s and runner B runs at 4.27m/s what will be

the distance between the runners at the end of the race?
Physics
1 answer:
natita [175]3 years ago
8 0

Answer:

pls give me brainliest

Explanation:

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Starting from rest and moving in a straight line, a cheetah
UNO [17]

The average acceleration of the cheetah is 7.75 m/s²

The given parameters;

velocity of the cheetah, v = 31 m/s

time of  motion, t = 4 seconds

The average acceleration of the cheetah is calculated as follows;

Average \ acceleration = \frac{\Delta velocity}{\Delta time } \\\\Average \ acceleration = \frac{v-u}{t}

where;

v is the final velocity

u is the initial velocity

t is the time of motion

Assuming the cheetah started from rest, the initial velocity, u = 0

The average acceleration is calculated as follows;

Average \ acceleration = \frac{v-u}{t} = \frac{31-0}{4} = 7.75 \ m/s^2

Thus, the average acceleration of the cheetah is 7.75 m/s²

Learn more here: brainly.com/question/17280180

3 0
3 years ago
Precautions taken when doing experiment on simple pendulum​
olchik [2.2K]

Answer:

1.)The bob of pendulum should be displaced with a small angle.

2) The amplitude of the oscillation of a simple pendulum should be small.

3) Fans should be switched off to reduce the air resistance.

4)The simple pendulum should be oscillate in a vertical plane

Hope this helped you

7 0
4 years ago
what do i wright: You are a drop of water going through the water cycle. Where do you go? How do you get there? What processes d
kenny6666 [7]

Explanation:

As the Sun heats the ocean, the water evaporates, turning into a gas. Sometimes this gas meets cooler air, and the gas changes into drops of water. This process is called condensation. Drops of water fall back down to Earth again as precipitation, which can be in the form of rain, snow, sleet, or hail

three phases of water cycle are

evaporation, condensation, <em>precipitation</em>

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7 0
3 years ago
newton's second law state that a force on a drag racer is equal to the mass of the car times it's acceleration. one of the most
kaheart [24]
I believe the answer you are looking for is the friction of the tires on the race track
7 0
4 years ago
Read 2 more answers
A forklift holds a 500 kg box 4 m in the air for 100 s. what is the minimum power required by the forklift
sineoko [7]
First of all, we need to calculate the work done by the forklift to lift the box of 500 kg by 4 meters. The work done is equal to the variation of gravitational potential energy of the box, given by:
W=\Delta U=mg\Delta h
where m=500 kg is the mass of the box, g=9.81 m/s^2 and \Delta h=4 m is the variation of height of the box. Substituting these data into the equation, we find the work
W=mg\Delta h=(500 kg)(9.81 m/s^2)(4 m)=19620 J

And now we can calculate the minimum power required by the forklift, which is equal to the ratio between the work done and the time taken:
P= \frac{W}{t}= \frac{19620 J}{100 s}=196.2 W
3 0
3 years ago
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