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3 years ago

What dose 3x-5y=15 and 2x-y=-4 really equel

Mathematics

2 answers:

podryga [215]3 years ago

6 0

3x - 5y = 15 -----> 1
2x - y = -4 ------>2
multiply eqn2 by -5 and add eqn 1
3x-5y = 15
-10x +5y = 20
--------------------
-7x = 35
x = -5
sub in eqn 2
2(-5) - y = -4
-10 - y = -4
-y = -4+10
-y = 6
y = -6
so the answer is (-5, -6)

myrzilka [38]3 years ago

4 0

The correct answer would be (-5,-6). Hope that helps!

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2 years ago

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Step-by-step explanation:

given that f(x) = sin x

we have to find the Taylor series for that

$f(x) = sin x : f( = 1\\f'(x) = cos x :(f'\frac{\pi}{2})=0\\f"(x) = -sinx :f" (\frac{\pi}{2}) =-1\\f^4 (x) = -cosx : f^4 (\frac{\pi}{2}) =0$

and so on.

i.e. 2nd, 4th, 6th terms would be 0

and also 1st, 5th, 9th terms would be positive for f value and 3rd, 9th,... would be negative

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$f(x) = f(a)+\frac{f'(a)}{1!} (x-\frac{\pi}{2}) +...+f^n(a) /n! (x- \frac{\pi}{2})^n+...$

$sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...$

This is valid for all real values of x.

x ∈ $(-\infty, infty)$

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