If riding a lawnmower engine exerts 19 hp in one minute to move the lawnmower how much work is done
1 answer:
Answer:
the work done by the lawnmower is 236.14 J.
Explanation:
Given;
power exerted by the lawnmower engine, P = 19 hp
time in which the power was exerted, t = 1 minute = 60 s.
1 hp = 745.7 watts
The work done by the lawnmower is calculated as follows;
Therefore, the work done by the lawnmower is 236.14 J.
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Answer:
Choices A, B, and C are correct.
Explanation:
Let us look at each of the choices one by one:
A. It is a vector
Yes. Velocity is a vector, or it's a speed with direction.
B. It is the change in displacement divided by the change in time.
Yes. The velocity can be written as
where is the displacement—a vector quantity.
C. It can be measured in meters per second.
Yes. The units of velocity are m/s, but also with a unit vector indicating the direction.
D. It is the slope of the acceleration vs. time graph.
Nope. The velocity is the slope of displacement vs. time graph.
Hence, only choices A, B, and C are correct.
Answer:
Step 1
Given: A tank is drained through an orifice from initial liquid level (h₀). The time(r), to drain the tank, depends on tank diameter (D), orifice diameter (d), acceleration due to gravity (g), liquid density (ρ) and liquid viscosity (μ).
r = f (h₀, D, d, g, ρ, μ)
Step 2
There are totally seven parameters r, h₀, D, d, g, ρ and μ
∴ n = 7
The primary variables are M, L, T
∴ m = 3
So, the number of repeating variables are, r = 3
Select the three repeating variables are ρ, d, g
Then according to Buckingham, there will be n-m (⇒ 7-3 = 4) dimensionless groups given by π₁, π₂, π₃ and π₄
So, The number of π terms = 4
Explanation:
See attached images for step 3 to 7
