a centrifugal clutch works, as the name suggests, through centrifugal force. ... The rotation of the hub forces the shoes or flyweights outwards until they come into contact with the clutch drum, the friction material transmits the torque from the flyweights to the drum. The drive is then connected
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The work done by the applied force = 650 J
Given the mass of the box = 40 kg
The displacement of the box on applying force = 5 m
Applied horizontal force = 130 N
The co-efficient of friction between box and floor is = 0.3
We have to find the work done by the applied force.
Work done by the applied force = Applied Force x Displacement of the box
= 130 N x 5 m
= 650 J
[Here the unit Nm is known as Joule(J) ]
We have the co-efficient of friction. So,
The force applied due to friction = Mass of the box x Co-efficient of friction x Acceleration due to gravity
= 40 kg x 0.3 x 9.8
= 117.6 N
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Answer:
The correct answer is D)
Explanation:
When an electric magnet is brought near a cord with an electric current, the cord will most likely deflect away from the magnet because electric fields flowing through a wire generates its own magnetic field.
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Answer:
a).p=15.67kg*m/s
b). F=7.83N
Explanation:
change in momentum is the subtraction from "after momentum" of the "before momentum" as momentum is a vector quantity this is a vector subtraction.
initial momentum of ball
m1v1 = (0.145)(44.0) = 6.38 kg-m/s
after momentum
m1v2 = (0.145)(64.0) = 9.28 kg-m/s
since these momentums are 180° opposite one must be called negative so their difference
6.38+9.28= 15.67 kg-m/s
change in momentum = 15.67 kg-m/s ANS a1
Impulse = change in momenutm = 15.67 ANS a2
b)
Impulse =Favg*t
I=(2.00)Favg
Impulse from (a2) = 15.67
Favg = 15.67/2.00 =
F= 7.83 N
