Answer:
41.0 m/s, 10.6 s
Explanation:
Given:
a = -4.8 m/s²
Δy = 165 m
v = -10.0 m/s
Find: v₀ and t
v² = v₀² + 2aΔy
(-10.0 m/s)² = v₀² + 2(-4.8 m/s²) (165 m)
v₀ = 41.0 m/s
Δy = vt − ½ at²
165 m = (-10.0 m/s) t − ½ (-4.8 m/s²) t²
165 = -10t + 2.4t²
0 = 2.4t² − 10t − 165
Solve with quadratic formula:
t = [ -(-10) ± √((-10)² − 4(2.4)(-165)) ] / 2(2.4)
t = (10 ± √1684) / 4.8
t = 10.6 s
Answer:
DUNNO
Explanation:
BIT BAD FOR 65% WOULD GET -100%
To solve this question, we use the wave equation which is:
C=f*λ
where:
C is the speed;
f is the frequency;
λ is the wavelength
So in this case, plugging in our values in the problem. This will give us:
C = 261.6Hz × 1.31m
= 342.696 m/s is the answer.
A car speeds up on how its built
