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Nataliya [291]
3 years ago
15

Rewrite the function f(x)=4(x-2)²-8 in the form f(x)=ax²+bx+c.

Mathematics
1 answer:
irinina [24]3 years ago
5 0

Answer:

lma ooo how many times did you post

4x^2 - 16x + 8

Step-by-step explanation:

4(x-2)^2-8

4(x-2)(x-2)-8

4{x^2-4x+4}-8

4x^2 - 16x +16 - 8

4x^2 - 16x + 8

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The unit digit of a two digit number is one less than the ten digit number. If the number is increase by 8 and then divided by t
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The tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.

<em>Lets simplify the problem,</em>

Let assume  the "tens" digit be x

Then the "units" difference =  (x-1), according to the condition.

Hence, the number itself is N = 10x + (x-1).

Then the number N+8 is 10x + (x-1) + 8 = 10x + x + 7 = 11x + 7.

From the last statement of the problem, we have this equation

N+8 = 8*(x+y),or11x + 7 = 8*(x+(x-1)).

Simplify and find "x"

11x + 7 = 8*(2x-1)11x + 7 = 16x - 87 + 8 = 16x - 11x15 = 5xx = 15/5 = 3.

Thus the tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.

Learn more about UNIT Problems on:

brainly.com/question/12253743

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2 years ago
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