Answer:
Reacciones de neutralización
Mg(OH)2
NaHCO3
Bicarbonato de sodio
Cloruro de sodio
Reacciones acido base
HCl + NaOH → NaCl + H2O.
H2SO4 + 2 NaOH → Na2SO4 + H2O.
HCl + NH3 → NH4Cl + H2O.
HCN + NaOH → NaCN + H2O.
Explanation:
Answer:
4, 16,
Explanation:
SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).
Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.
Oxidation half reaction is written as follows when using using reduction potential chart
example when using copper it is written as follows
CU2+ +2e- --> c(s) +0.34v
oxidasation is the loos of electron hence copper oxidation potential is as follows
cu (s) --> CU2+ +2e -0.34v
Iron rusts when exposed to air → chemical property
