Answer:
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Explanation:
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Answer:
a)
1-Pentanamine
2-Pentanamine
3-Pentanamine
3-methyl-2-butanamine
3-methyl-1-butanamine
2-methyl-1-butanamine
2-methyl-2-butanamine
2,2-dimethyl-1-propanamine
b)
2-pentanamine
3-methyl-2-butanamine
2-methyl-1-butanamine
Explanation:
Amines are organic compounds derived from ammonia by replacing the hydrogen atoms, one at a time with carbon-containing groups. The functional groups are R-NH₂, R₂-NH, and R₃-N
Amines are classified into primary, secondary, or tertiary according to the number of substituted hydrogen.
From the given question.
A compound with the molecular formula C₅H₁₃N was given;
The possible eight structural formula of the compound and those that exhibit chirality can be seen in the attached image below.
The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g
<h3>Avogadro's hypothesis </h3>
6.02×10²³ formula units = 1 mole of CuF₂
But
1 mole of CuF₂ = 101.5 g
Thus,
6.02×10²³ formula units = 101.5 g of CuF₂
<h3>How to determine the mass of 8.94×10²² formula units of CuF₂</h3>
6.02×10²³ formula units = 101.5 g of CuF₂
Therefore,
8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³
8.94×10²² formula units = 15.07 g of CuF₂
Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂
Learn more about Avogadro's number:
brainly.com/question/26141731
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Answer:
Explanation:
The oxidation number is an integer that represents the number of electrons that an atom receives or makes available to others when it forms a given compound.
The oxidation number is positive if the atom loses electrons, or shares them with an atom that has a tendency to accept them. And it will be negative when the atom gains electrons, or shares them with an atom that has a tendency to give them up.
Chemical compounds are electrically neutral. That is, the charge that all the atoms of a compound contribute must be globally null. That is, when having positive or negative charges in a compound, their sum must be zero.
There are some rules for determining oxidation numbers in compounds. Among them it is possible to mention:
- Hydrogen (H) has an oxidation number +1 with nonmetals and - 1 with metals.
- Oxygen (O) presents the oxidation number -2
- Fluorine F has a unique oxidation state -1
Then:
- NOF: N+(-2)+(-1)=0 → N=3 → oxidation number of nitrogen (N) is +3, oxidation number of oxygen (O) is -2 and oxidation number of fluorine (F) is -1.
- ClF₅: Cl + 5*(-1)=0 → Cl= 5 → oxidation number of chlorine (Cl) is +5 and oxidation number of fluorine (F) is -1.
- H₂SO₃: 2*(+1)+S+3*(-2)=0 → S=4 → oxidation number of hydrogen (H) is +1, oxidation number of oxygen (O) is -2 and oxidation number of sulfur (S) is +4.
Answer:
Explanation:Do you like to draw coz you put the D in raw
