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2 years ago

Solve. -5 3/4-3 1/2=?

Mathematics

1 answer:

g100num [7]2 years ago

6 0

Answer: -9 1/4.

Step-by-step explanation:

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Use the picture to create a ratio between the objects.

Julli [10]

Answer:Blue

Step-by-step explanation:

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2 years ago

Karen is working on her math homework. She solves the equation

Gelneren [198K]

Disagree.
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3 years ago

T = an + b ( solve for b )

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B=t-am is the correct answer:)

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3 years ago

3(-0.4n-0.7)=-3.2n-2.58

svlad2 [7]

Answer:

$n=-0.24$

Step-by-step explanation:

$3\left(-0.4n-0.7\right)=-3.2n-2.58$

Use distributive property.

$-1.2n-2.1=-3.2n-2.58$

$-1.2n-2.1+2.1=-3.2n-2.58+2.1$

$-1.2n=-3.2n-0.48$

$-1.2n+3.2n=-3.2n-0.48+3.2n$

$2n=-0.48$

$\frac{2n}{2}=\frac{-0.48}{2}$

$n=-0.24$

3 0

3 years ago

You find an interest rate of 10% compounded quarterly. Calculate how much more money you would have in your pocket if you had us

Elena-2011 [213]

Answer:

see the explanation

Step-by-step explanation:

we know that

step 1

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$r=10\%=10/100=0.10\\n=4$

substitute in the formula above

$A=P(1+\frac{0.10}{4})^{4t}$

$A=P(1.025)^{4t}$

Applying property of exponents

$A=P[(1.025)^{4}]^{t}$

$A=P(1.1038)^{t}$

step 2

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$r=10\%=10/100=0.10$

substitute in the formula above

$A=P(e)^{0.10t}$

Applying property of exponents

$A=P[(e)^{0.10}]^{t}$

$A=P(1.1052)^{t}$

step 3

Compare the final amount

$P(1.1052)^{t} > P(1.1038)^{t}$

therefore

Find the difference

$P(1.1052)^{t} - P(1.1038)^{t}$ ----> Additional amount of money you would have in your pocket if you had used a continuously compounded account with the same interest rate and the same principal.

3 0

3 years ago