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ryzh [129]
3 years ago
5

How is hydrogen in heavy water different from hydrogen in normal water?

Chemistry
2 answers:
MariettaO [177]3 years ago
7 0

Answer:

Its c

Explanation:

Because I did it

I am Lyosha [343]3 years ago
6 0

Answer:C

Explanation:Apex

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When copper metal is heated to 1100 oC it melts. Is this a chemical or physical change? Explain your answer
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Answer:

it is a physical change

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How many electrons are in the outermost principal energy level of an atom of carbon in the ground state
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Answer:

four electrons

Explanation:

Let us attempt to write the electronic configuration of carbon in the ground state. This electronic configuration will now be;

C- 1s2 2s2 2p2

The outermost principal energy level of carbon is the n=2 level which houses the 2s2 and 2p2, making a total of four electrons in the outermost principal energy level of an atom of carbon in the ground state.

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3 years ago
How much pollution is in urban streams ?
Marizza181 [45]

Explanation: Pollution in urban streams (commonly caused by improperly disposed waste and/or acid rain) always has a negative effect on the environment. <em>Urban rivers are extremely polluted in some areas</em>, such as India. Actions have been taken to clear the streams, and progress has been made.

Hope this helps!

7 0
4 years ago
A compound that contains only carbon, hydrogen, and oxygen is 58.8% C and 9.87% H by mass. What is the empirical formula of this
Dmitry [639]

<u>Answer:</u> The empirical formula of the compound becomes C_5H_{10}O_2

<u>Explanation:</u>

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

Let the mass of the compound be 100 g

Given values:

% of C = 58.8%

% of H = 9.87%

% of O = [100 - 58.8 - 9.87] = 31.33%

Mass of C = 58.8 g

Mass of H = 9.87 g

Mass of O = 31.33 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of C}=\frac{58.8g}{12g/mol}=4.9 mol

\text{Moles of H}=\frac{9.87g}{1g/mol}=9.87 mol

\text{Moles of O}=\frac{31.33g}{16g/mol}=1.96mol

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 1.96 moles

\text{Mole fraction of C}=\frac{4.9}{1.96}=2.5

\text{Mole fraction of H}=\frac{9.87}{1.96}=5.03\approx 5

\text{Mole fraction of O}=\frac{1.96}{1.96}=1

Converting the mole fraction into whole numbers by multiplying them with 2.

\text{Mole fraction of C}=2.5\times 2=5

\text{Mole fraction of H}=5\times 2=10

\text{Mole fraction of O}=1\times 2=2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 5 : 10 : 2

Hence, the empirical formula of the compound becomes C_5H_{10}O_2

8 0
3 years ago
HELP! me please help with this science assignment
Elina [12.6K]
I’m not sure about the rest but 4 is families
7 0
3 years ago
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