Answer: The time period of about 1 msec after an action potential before another one can be initiated -----b
Explanation:Absolute refractory period is the time after an action potential onset when no amount or how strong a stimulus is can cause a second action potential. it is always the time period of 1 m sec between an initiated action potential and an impending next initiated one with the the maximum firing frequency at about 1000 impulses per second.
The absolute refractory period is as a result of molecular processes that triggers the action potential known as sodium channels(tiny pore nerves) . Now the sodium channels exist in three states which are open, close and inactivated states. At rest, the sodium channel is closed, but when a there is an electrical stimulation, the sodium channel opens up to respond to that stimulus which after it passes to the inactivated state, in which the the spores are closed and no matter how strong or the amount an impending next stimulus is, will not cause the pore to open until it has recovered and returned back to the closed state.
Answer:
<em><u>Various effects can be seen when the current is flown in a circuit. The major effects of electric current are heating, chemical, and magnetic effects.Passage of current through chemical solutions causes chemical reactions to require place.</u></em>
Explanation:
<em>I</em><em> </em><em>hope</em><em> </em><em>its</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>u</em>
X + 8 where x = 6
6 + 8 = 14
For the answer to the question above, <span>The formula for freezing point depression is </span>
<span>ΔTf = mkfi </span>
<span>kf is the freezing point constant </span>
<span>i is the Van't Hoff factor which in this case is 1 </span>
<span>m is molality (moles of solute/kg of solvent) </span>
<span>ΔTf is temperature change </span>
<span>ΔTf is 2.17 °C, the molality is the amount of solute Quinine </span>
<span>in the solvent cyclohexane. We cannot calculate moles therefore we need to substitute moles with g/mm. </span>
<span>moles = g/mm so molality=(g/mm)/kg </span>
<span>molality = (0.845/mm)/0.025 = 33.8/mm </span>
<span>2.17 = 33.8/mm(20.8) rearrange </span>
<span>mm = (33.8/2.17)(20.8) = 324g/mol</span>
