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3 years ago

Define each of these dimensions of development: physical, cognitive, psychosocial, and moral. (8 points)

Physics

1 answer:

Kruka [31]3 years ago

3 0

Answer:

Explanation:

Physical development refers to the growth, physical and biological changes that happens in the humans body between birth and till they get to adolescence stage. There is development in brain, senses, they way they talk, physical appearance e.r.c.

Examples of these include, as humans grow, there is an increase in the way they interact with other people.

Babies tend to interact and learn new words even as their sense organs are been developed.

Cognitive development refers to how children develop in knowledge, skills, they way they think, their disposition and problem solving ability. These help children to think and understand their environment better.

Psychosocial development entails psychological and social development and it refers to how human personality is developed, acquiring social attitudes and skills from young age to adult. It entails how humans interact with their environment.

Moral development entails changes that occur in humans from childhood to adulthood by possesing the the skills and ability to know what is right and what is wrong i.e an understanding of morals behavior.

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son4ous [18]

Answer:

The answer is 13 however make sure if they ask for a certain measurement like meter answer it by saying 13 meters.

Explanation:

This basically turns into basic algebra if you know the formula for work. The formula for work is W=F*d

Here are the variables that you know 650J=50N*d so you need d.

All you do is divide 650J by 50N and you get a total of 13 (meters since I don't know what they want you to put it in).

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A 5.0-μC charge is placed at the 0 cm mark of a meter stick and a -4.0 μC charge is placed at the 50 cm mark. At what point on a

Maksim231197 [3]

Answer:

The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

Explanation:

Given that

q₁ = 5 μ C

q₂ = - 4 μ C

The distance between charges = 50 cm

d= 50 cm

Lets take at distance x from the charge μ C ,the electrical field is zero.

That is why the distance from the charge - 4 μ C = 50 - x cm

We know that ,electric field is given as

$E=K\dfrac{q}{r^2}$

$K\dfrac{5\ \mu}{x^2}=K\dfrac{4\mu }{(50-x)^2}\\\\\dfrac{5}{x^2}=\dfrac{4 }{(50-x)^2}\\\\\\5(50-x)^2=4x^2\\(50-x)^2=0.8x^2\\\\50-x =0.89x\\\ x=\dfrac{50}{1.89}\ cm\\\\\\x=26.45\ cm\\$

Therefore the distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

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Explanation:

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Hello there.

Its D.

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