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2 years ago

Define each of these dimensions of development: physical, cognitive, psychosocial, and moral. (8 points)

Physics

1 answer:

Kruka [31]2 years ago

3 0

Answer:

Explanation:

Physical development refers to the growth, physical and biological changes that happens in the humans body between birth and till they get to adolescence stage. There is development in brain, senses, they way they talk, physical appearance e.r.c.

Examples of these include, as humans grow, there is an increase in the way they interact with other people.

Babies tend to interact and learn new words even as their sense organs are been developed.

Cognitive development refers to how children develop in knowledge, skills, they way they think, their disposition and problem solving ability. These help children to think and understand their environment better.

Psychosocial development entails psychological and social development and it refers to how human personality is developed, acquiring social attitudes and skills from young age to adult. It entails how humans interact with their environment.

Moral development entails changes that occur in humans from childhood to adulthood by possesing the the skills and ability to know what is right and what is wrong i.e an understanding of morals behavior.

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Answer:

D. Meters/Seconds

Explanation:

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2 years ago

What is the force felt by the 64-kg occupant of the car? Express your answer to two significant figures and include the appropri

Yakvenalex [24]

Answer:

The force is $-1.67\times10^{5}\ N$

Explanation:

Given that,

Mass of car = 64 kg

Suppose, a 1400-kg car that stops from 34 km/h on a distance of 1.7 cm.

We need to calculate the acceleration

Using formula of acceleration

$v^2-u^2=2as$

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value into the formula

$0^2-(34\times\dfrac{5}{18})^2=2\times a\times 1.7\times10^{-2}$

$a=\dfrac{(34\times\dfrac{5}{18})^2}{2\times1.7\times10^{-2}}$

$a=-2623.45\ m/s²$

We need to calculate the force

Using formula of force

$F=ma$

$F=64\times(-2623.45)$

$F=-1.67\times10^{5}\ N$

Negative sign shows the direction of the force is in the direction opposite to the initial velocity.

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3 years ago

1 2 3 4 5 6 7 8 9 10

7nadin3 [17]

Answer:

<h2>C. 0.55 m/s towards the right</h2>

Explanation:

Using the conservation of law of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Momentum = Mass (M) * Velocity(V)

BEFORE COLLISION

Momentum of 0.25kg body moving at 1.0m/s = 0.25*1 = 0.25kgm/s

Momentum of 0.15kg body moving at 0.0m/s(body at rest) = 0kgm/s

AFTER COLLISION

Momentum of 0.25kg body moving at x m/s = 0.25* x= 0.25x kgm/s

x is the final velocity of the 0.25kg ball

Momentum of 0.15kg body moving at 0.75m/s(body at rest) =

0.15 * 0.75kgm/s = 0.1125 kgm/s

Using the law of conservation of momentum;

0.25+0 = 0.25x + 0.1125

0.25x = 0.25-0.1125

0.25x = 0.1375

x = 0.1375/0.25

x = 0.55m/s

Since the 0.15 kg ball moves off to the right after collision, the 0.25 kg ball will move at 0.55 m/s towards the right

4 0

2 years ago