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blagie [28]
3 years ago
13

When a strontium atom loses two electrons to form an Sr2+ ion, the electrons are lost from the

Chemistry
1 answer:
kherson [118]3 years ago
6 0

Answer:When a strontium atom loses two electrons, it becomes a(n) cation with a charge of 2+. when any neutral atom loses an electron it becomes cation that is positively charged ions and an ion gets the charge according to the number of electrons loses.

you are very welcome but I may be inaccurate.

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Guanidin HNC(NH2)2 is a fertilizer. What is the percent by mass of nitrogen in the fertilizer
Katyanochek1 [597]

Answer:

71.1%. , is a fertilizer.

7 0
2 years ago
I in the blanks.<br>The solid substance left on the filter paper is called​
horsena [70]

Explanation:

the solid substance which left on the filter paper is called Residue

3 0
3 years ago
If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
2 years ago
Which element is reduced in this reaction? 2kmno4 3na2so3 h2o→2mno2 3na2so4 2koh
erik [133]

In a redox chemical reaction, one species gets reduced and another gets oxidized. Manganese element is reduced in this reaction.

<h3>What is oxidized and reduced?</h3>

In a redox reaction, the increase or decrease in the oxidation number and electrons results in the reduction and oxidation of the chemical species. The oxidation and reduction occur simultaneously in a reaction.

The oxidation number of Mn in permanganate ion was +8 on the left side and decreased to +4 on the right side of the equation. Potassium permanganate is an oxidizing agent that has reduced the manganese ion of the permanganate ion.

Therefore, manganese is reduced.

Learn more about reduction and oxidation here:

brainly.com/question/2427143

#SPJ4

3 0
2 years ago
Copper(II) sulfate is an active ingredient in tree stump remover. In order to help remove
Eva8 [605]

Answer:

the tree red

Explanation:

7 0
2 years ago
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