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Sindrei [870]
3 years ago
5

Besides filament-based detectors, what else are sometimes used to find flammable liquids?

Chemistry
1 answer:
Anettt [7]3 years ago
6 0

Answer:

D

Explanation:

can u be my friend i'm new

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At constant P and n, T decreases at V is?
goblinko [34]

Answer:

This means that as pressure increases,the volume decreases or the volume increases as the temperature increases, and decreases as the temperature decreases

8 0
3 years ago
Of molecules didn't exist how would life be different
UNO [17]
Everything is made of molecules so I don’t think there would be life without molecules..
8 0
3 years ago
Read 2 more answers
In a chemical process, the amount of a certain type of impurity in the output is difficult to control and is thus a random varia
Julli [10]

Answer:

+/- 0.00033

Explanation:

For a 95 % confidence interval the range is given by

+/- Z * s/sqrt(n)

where Z value is 1.916 for a 95% confidence interval

Therefore the interval is

s is the standard deviation in this case 0.0015

n is 75 the number of outposts

calculating,

+/- 1.916 * 0.0015/sqrt(75) = +/- 0.00033

8 0
3 years ago
Read 2 more answers
Write the answer in scientific notation when you multiply 2 x 104 by 3 x 104.
emmasim [6.3K]

Answer:

6× 10⁸

Explanation:

We need to find the multiplication of 2 x 10⁴ by 3 x 10⁴.

2 x 10⁴ × 3 x 10⁴

= (3 × 2) x 10⁴ x 10⁴

= 6 x 10⁴ x 10⁴

= 6 × 10⁴⁺⁴

= 6× 10⁸

Hence, the required answer is 6× 10⁸.

7 0
3 years ago
A compound with a molar mass of 60g/mol is 40.4% carbon, 6.7% hydrogen and 53.3% oxygen (by mass). determine the emperical and m
Fittoniya [83]

<span>A compound is found to be 40.0% carbon, 6.7% hydrogen and 53.5% oxygen. Its molecular mass is 60. g/mol. 
</span>Q1)
Empirical formula is the simplest ratio of whole numbers of components making up a compound.
the percentages have been given, therefore we can calculate for 100 g of the compound.

                                C                            H                        O
Mass in 100 g      40.0 g                       6.7 g                   53.5 g
Molar mass            12 g/mol                1 g/mol                 16 g/mol
Number of moles   40.0/12= 3.33         6.7/1 = 6.7          53.5/16 = 3.34
Divide by the least number of moles  
                             3.33/3.33 = 1           6.7/3.33 = 2.01   3.34/3.33 = 1.00
after rounding off
C - 1 
H - 2
O - 1

Empirical formula - CH₂O

Q2)
Molecular formula is the actual number of components making up the compound.
To find the number of empirical units we have to find the mass of one empirical unit.
Mass of one empirical unit = CH₂O - 12 + (1x2) + 16 = 30 g
Mass of one mole of compound = 60 g
Number of empirical units = 60 g / 30 g = 2
Therefore molecular formula - 2(CH₂O) 
 Molecular formula - C₂H₄O₂
4 0
3 years ago
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