To balance chemical equations, what must be done is the same number of each element in the input must be present in the output. For example, photosynthesis.
H2O + CO2 —> C6H12O6 + O2
As can be deduced, the input only has 2 H, 1 C, and 3 O. Whereas, the output has 6 C, 12H, and 6 O. When balancing I recommend to balance the unique elements if possible (for example, H is only in one molecule on each side)
So you get 6(H2O) + 6(CO2) —> C6H12O6 + 6(O2)
Hope this helped!
Answer: A pattern of same atomic orbitals can be seen about elements in the same period with respect to electron structures.
Explanation:
The horizontal rows in a period table are called periods.
Elements present in the same period will have same atomic orbitals.
For example, electronic distribution of Na is 2, 8, 1 and it is a third period element.
Similarly, electronic distribution of Cl is 2, 8, 7 and it is also a third period element.
Hence, both Na and Cl will have K, L, M shells, that is, they have three atomic orbitals.
Thus, we can conclude that a pattern of same atomic orbitals can be seen about elements in the same period with respect to electron structures.
Answer:
Kp and Kc are 0.01266 and 145.17, respectively.
Explanation:
Please check document attached.
Answer:
0.482 ×10²³ molecules
Explanation:
Given data:
Volume of gas = 2.5 L
Temperature of gas = 50°C (50+273 = 323 k)
Pressure of gas = 650 mmHg (650/760 =0.86 atm)
Molecules of N₂= ?
Solution:
PV= nRT
n = PV/RT
n = 0.86 atm × 2.5 L /0.0821 atm. mol⁻¹. k⁻¹. L × 323 k
n = 2.15 atm. L /26.52 atm. mol⁻¹.L
n = 0.08 mol
Number of moles of N₂ are 0.08 mol.
Number of molecules:
one mole = 6.022 ×10²³ molecules
0.08×6.022 ×10²³ = 0.482 ×10²³ molecules
Answer:
i think its 10 miles per hour