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Sindrei [870]
3 years ago
5

Besides filament-based detectors, what else are sometimes used to find flammable liquids?

Chemistry
1 answer:
Anettt [7]3 years ago
6 0

Answer:

D

Explanation:

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What are the missing coefficients for the skeleton equation below?
Kruka [31]

Answer:

4, 3 , 2 and 6

Explanation:

The reaction equation is given as;

       NH₃  +  O₂   →    N₂   +   H₂O

Now, we need to balance the reaction equation;

     NH₃  +  O₂   →    N₂   +   H₂O

put the numbers a,b,c and d;

    aNH₃  +  bO₂   →    cN₂   +   dH₂O  

We need to balance the equation algebraically, ;

  Conserving N;

      a = 2c

   Conserving H;

      3a  = 2d

   Conserving O;

      2b  = d

Now, let c = 1, a = 2, d  = 3 and b  = \frac{3}{2}  

  multiply through by 2;

            a  = 4, b = 3, c  = 2 and d  = 6

Insert the parameters:

                  4NH₃  +  3O₂   →    2N₂   +   6H₂O

4 0
3 years ago
Chemistry mixes 108 g of O2, with 232 L of C3Hg at STP. How many grams of H2O will be produced? The balanced equation for this r
mart [117]
We are given the following data.amount of oxygen gas mixed=108 grams molar mass of oxygen gas 32 g/mol volume of c3h8ch8.
7 0
2 years ago
Please help asap! This is the last question for my chemistry test!
stepan [7]

Answer:

i took the test but failed and just got that question right so b

Explanation:

4 0
3 years ago
Carbon-14 has a half-life of 5,700 years.
Maksim231197 [3]

Answer:

3.106\ \text{g}

Explanation:

t_{1/2} = Half-life of carbon = 5700 years

t = Time at which the remaining mass is to be found = 10400 years

m_0 = Initial mass of carbon = 11 g

Decay constant is given by

\lambda=\dfrac{\ln2}{t_{1/2}}

Amount of mass remaining is given by

m=m_0e^{-\lambda t}\\\Rightarrow m=m_0e^{-\dfrac{\ln2}{t_{1/2}} t}\\\Rightarrow m=11e^{-\dfrac{\ln 2}{5700}\times 10400}\\\Rightarrow m=3.106\ \text{g}

The amount of the substance that remains after 10400 years is 3.106\ \text{g}.

5 0
3 years ago
When one mole of sodium chloride dissociates in water, it produces: 1 mole of ions ½ mole of sodium ions 2 moles of ions ½ mole
adelina 88 [10]
Dissociation of NaCl in water is given as below,

                             NaCl ₍s₎    →    Na⁺ ₍aq₎  +  Cl⁻ ₍aq₎

According to this balanced equation the moles on RHS and LHS are as,

Moles on LHS,
                           NaCl ₍s₎   =   1 Mole

Moles on RHS,
                          Na⁺ ₍aq₎   =   1 Mole

                           Cl⁻ ₍aq₎   =    1 Mole
Result:
           
<span>When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.</span>
7 0
3 years ago
Read 2 more answers
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