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labwork [276]
3 years ago
14

A flexible vessel contains 32.00 L of gas at a pressure of 1.59 atm. Under conditions of constant temperature and moles of gas,

what is the volume of the gas when the pressure of the vessel is decreased by a factor of three
Chemistry
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

When the pressure of the vessel is decreased by a factor of three, the volume will increase by a factor 3. This means the new volume is 96.00 L

Explanation:

Step 1: Data given

Volume of the gas = 32.00 L

Pressure of the gas = 1.59 atm

Temperature and moles of gas stay constant

the pressure of the vessel is decreased by a factor of three

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 1.59 atm

⇒with V1 = the initial volume = 32.00 L

⇒with P2 = the decreased pressure = 1.59 / 3 = 0.53 atm

⇒with V2 = the new volume = TO BE DETERMINED

1.59 atm * 32.00 L = 0.53 atm * V2

V2 = (1.59 * 32.00 L) / 0.53 atm

V2 = 96.00 L

When the pressure of the vessel is decreased by a factor of three, the volume will increase by a factor 3. This means the new volume is 96.00 L

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Which compound is an isomer of propanoic acid (CH3CH2COOH)?
arlik [135]

Answer:

D) HCOOCH2CH3

Explanation:

An isomer of a compound is defined as a chemical substances with the same formula (That is, same atoms) but in different structures.

For propanoic acid, there are <em>3 atoms of C, 6 atoms of H and 2 atoms of oxygen.</em>

A) CH2CHCOOH . Here you have 3 atoms of C but 4 atoms of H. That means this compound is not an isomer.

B) CH3CH2CH2COOH . Here, there are 4 atoms of C. Thus, is not an isomer.

C) CH3CH(OH)CH2OH. This structure has 3 atoms of C, but 8 atoms of H. Thus, is not an isomer.

D) HCOOCH2CH3. Here, there are 3 atoms of C, 6 atoms of H and 2 atoms of O. Thus, this structure <em>is an isomer of propanoic acid.</em>

5 0
2 years ago
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What is the empirical formula of a compound containing 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen?
Anvisha [2.4K]

Answer:

= C3H4N

Explanation:

We are given; 90 grams carbon, 11 grams hydrogen, and 35 grams nitrogen.

We first calculate the number of moles of each element.

Carbon = 90g/12 g/mol

            = 7.5 moles

Hydrogen = 11 g/ 1 g/mol

                 = 11 moles

Nitrogen = 35 g/ 14 g/mol

               = 2.5 moles

The we get the mole ratio of the elements;

= 7.5/2.5 : 11/2.5 : 2.5 /2.5

= 3 : 4.4 : 1

= 3 : 4 : 1

Therefore;

The empirical formula will be; C3H4N

6 0
3 years ago
How many atoms are in 50 moles of Al
Lemur [1.5K]

Answer:

There are 3 atoms in the 50 moles of Al

Explanation:

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2 years ago
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Determine the resulting pH when 75 mL of 0.05M HBr is reacted with 74 mL of 0.075 M KOH
Sunny_sXe [5.5K]

Answer:

pH = 12.08

Explanation:

  • H⁺ + OH⁻ → H₂O

First we <u>calculate how many moles of each substance were added</u>, using <em>the given volume and concentration</em>:

  • HBr ⇒ 0.05 M * 75 mL = 3.75 mmol HBr
  • KOH ⇒ 0.075 M * 74 mL = 5.55 mmol KOH

As HBr is a strong acid, it dissociates completely into H⁺ and Br⁻ species. Conversely, KOH dissociates completely into OH⁻ and K⁺ species.

As there are more OH⁻ moles than H⁺ moles (5.55 vs 3.75), we <u>calculate how many OH⁻ moles remain after the reaction</u>:

  • 5.55 - 3.75 = 1.8 mmoles OH⁻

With that<em> number of moles and the volume of the mixture</em>, we <u>calculate [OH⁻]</u>:

  • [OH⁻] = 1.8 mmol / (75 mL + 74 mL) = 0.0121 M

With [OH⁻], we <u>calculate the pOH</u>:

  • pOH = -log[OH⁻] = 1.92

With the pOH, we <u>calculate the pH</u>:

  • pH = 14 - pOH
  • pH = 12.08
6 0
3 years ago
. zinc + nitrogen → zinc nitride
tangare [24]

Answer:

...................

.

6 0
2 years ago
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