Reaction is NaHCO3 + HCL = H2CO3 + NaCl
the ratios are 1:1
the 8 moles of HCl are in excess
so if you use 4 moles of NaHCO3 then you will obtain 4 moles of carbonic acid
hope that helps
Answer:
The answer is that ethane gas has a density of 1.34 g/L at STP
Explanation:
Ethane weighs 0.0013562 gram per cubic centimeter or 1.3562 kilogram per cubic meter, i.e. density of ethane is equal to 1.3562 kg/m³; at 0°C (32°F or 273.15K) at standard atmospheric pressure.
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Na 2Co3
1*23=23. 2*12=24. 6*16=96
23+24+96=143
(23*100)/143. (24*100)/143. (96*100)/143
=16%. =16.7%. =67.1%
Answer:
New pressure P2 = 4.95 atm
Explanation:
Given:
Old volume V1 = 1.50 L
New volume V2 = 0.50 L
Old pressure P1 = 1.65 atm
Find:
New pressure P2
Computation:
P1V1 = P2V2
So,
(1.50)(1.65) = (0.50)(P2)
New pressure P2 = 4.95 atm
