Answer
given,
Electric field,E = 490 N/C
time, t = 54 ns
for electron
Mass of electron me = 9.1 x 10⁻³¹ kg
Charge of electron e = -1.6 x 10⁻¹⁹ C
electrostatic force
F = E q
F = 490 x 1.6 x 10⁻¹⁹
F = 784 x 10⁻¹⁹ N
now, using newton second law
a = 8.62 x 10¹² m/s²
using equation of motion
v = u + a t
v = 0 + 8.62 x 10¹² x 54 x 10⁻⁹
v = 4.65 x 10⁵ m/s
velocity of electron is equal to v = 4.65 x 10⁵ m/s
For Proton
Mass mp = 1.67 x 10⁻²⁷ kg
Charge p = 1.6 x 10⁻¹⁹ C
Electric field E = 490 V/C
from above solution
F = 784 x 10⁻¹⁹ N
now, acceleration
a = 4.69 x 10¹⁰ m/s²
using equation of motion
v = u + a t
v = 0 + 4.69 x 10¹⁰ x 54 x 10⁻⁹
v = 4.65 x 10³ m/s
velocity of electron is equal to v = 4.65 x 10³ m/s
Yes, I do! Vectors have a direction linked to them and scalars don’t.
Answer:
<em>The second drop is 3.75 m above the ground</em>
Explanation:
<u>Free Fall Motion</u>
A free-falling object falls under the sole influence of gravity without air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is .
The distance traveled by a dropped object is:
If we know the height h from which the object was dropped, we can find the time it takes fo hit the ground:
When the first drop touches the ground there are two more drops in the air: the second drop still traveling, and the third drop just released from the tap.
The total time taken for the first drop to reach the ground is:
Half of this time has taken the second drop to fall:
It has fallen a distance of:
Thus its height is:
h = 5 - 1.25 = 3.75
The second drop is 3.75 m above the ground