3 years ago

What is the difference between the initial position and the final position of an object?

Physics

1 answer:

Grace [21]3 years ago

5 0

The initial is where you are starting and the final postion is where the object ends up

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A magnetic field is uniform over a flat, horizontal circular region with a radius of 1.50 mm, and the field varies with time. In

Daniel [21]

Answer: $81.57\mu V$

Explanation:

Given

radius of circular region r=1.50 mm

$A=\pi r^2=7.069\times 10^{-6}\ m^2$

Magnetic Field $B=1.50\ T$

time t=130 ms

Flux is given by

$\phi =B\cdot A$

change in Flux $d\phi =(B_f-B_i)A$

Emf induced is $e=\frac{\mathrm{d} \phi}{\mathrm{d} t}$

$e=\frac{(1.5)\cdot 7.069\times 10^{-6}}{130\times 10^{-3}}$

$e=81.57 \mu V$

3 0

3 years ago

The deepest well from which water can be pumped, by creating a vacuum on the top end of the pipe

Ivenika [448]

Can you further elaborate this isn't making much sense my mans

7 0

2 years ago

Why does the number of dwarf planets recognized by astronomers in the solar system sometimes increase?

gregori [183]

Because sometimes it happens that they discover a dwarf planet
that nobody ever knew about before. When that happens, they
ADD the new one to the list of known dwarf planets, and then the
total number of dwarf planets on the list increases by 1 .

4 0

3 years ago

Q3. A man walks with a speed of 8 m/sec in 40 sec. How much distance was covered?

chubhunter [2.5K]

Answer:

it is320 m.

Explanation:

by formula

d= m/s×t

d= 8× 40

d=320 m

8 0

2 years ago

Read 2 more answers

A truck is driving over a scale at a weight station. When the front wheels drive over the scale, the scale reads 5800 N. When th

aev [14]

Answer:

$x_2=1.60m$

Explanation:

From the Question We are told that

Initial Force $F_1=5800N$

Final Force $F_2=6500N$

Distance between the front and rear wheels \triangle x=3.20 m

Since

$\triangle x=3.20 m$

Therefore

$x_1+x_2=3.20$

$x_1=3.20-x_2$

Generally the equation for The center of mass is at x_2 is mathematically

given by

$x_2 =\frac{(F_1x_1+F_2x_2)}{(F_1+F_2)}$

$x_2=3.20F_1-\frac{x_2F_1+F_2x_2}{(F_1+F_2)}$

$2*F_1*x_2 =3.20F_1$

$x_2=1.60m$

6 0

2 years ago