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wolverine [178]
3 years ago
6

What is the difference between the initial position and the final position of an object?

Physics
1 answer:
Grace [21]3 years ago
5 0
The initial is where you are starting and the final postion is where the object ends up
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Two moles of He gas are at 25 degrees C and a pressure of 210 kPa. If the gas is heated to 48 degrees C and its pressure reduced
SpyIntel [72]

Answer:0.0686 m^3

Explanation:

Given

No of moles=2

T=25^{\circ}\approx 298 K

P_1=210 KPa

T_2=48 ^{\circ}\approx 321 k

P_2=77.7 KPa

PV=nRT

Substitute

77.7\times V_2=2\times 8.314\times 321

V_2=0.0686 m^3

4 0
3 years ago
In which tool are uranium atoms split to make electricity? A. turbine B. generator C. reactor D. condenser
svetoff [14.1K]
The tool that splits uranium atoms to make electricity is a nuclear reactor. A nuclear reactor is also known as an atomic pile.

Your answer is: C) Reactor 

Have an amazing day!

4 0
3 years ago
A velocity vs. time graph starts at 0 and ends at 10 m/s, stretching over a time- span of 15 s with constant acceleration. What
Alex777 [14]

Answer:

75m

Explanation:

6 0
3 years ago
If I can travel 20m in 18 seconds how far can I go in 10 minutes?
kifflom [539]

Answer:

36 s

Explanation:

20 m = 18 s

10 m = ?

20 × 18 = 360÷ 10

= 36 sec

5 0
3 years ago
A 5.00 g object moving to the right at 20.0 cm/s makes an elastic head-on collision with a 10.0 g object that is initially at re
marusya05 [52]

Answer: a) 6.67cm/s b) 1/2

Explanation:

According to law of conservation of momentum, the momentum of the bodies before collision is equal to the momentum of the bodies after collision. Since the second body was initially at rest this means the initial velocity of the body is "zero".

Let m1 and m2 be the masses of the bodies

u1 and u2 be their velocities respectively

m1 = 5.0g m2 = 10.0g u1 = 20.0cm/s u2 = 0cm/s

Since momentum = mass × velocity

The conservation of momentum of the body will be

m1u1 + m2u2 = (m1+m2)v

Note that the body will move with a common velocity (v) after collision which will serve as the velocity of each object after collision.

5(20) + 10(0) = (5+10)v

100 + 0 = 15v

v = 100/15

v = 6.67cm/s

Therefore the velocity of each object after the collision is 6.67cm/s

b) kinectic energy of the 10.0g object will be 1/2MV²

= 1/2×10×6.67²

= 222.44Joules

kinectic energy of the 5.0g object will be 1/2MV²

= 1/2×5×6.67²

= 222.44Joules

= 111.22Joules

Fraction of the initial kinetic transferred to the 10g object will be

111.22/222.44

= 1/2

3 0
4 years ago
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