We Know, F = m*a
F = 2200 * 3.4
F = 7480 Kg m/s²
So, your final answer is 7480
Answer:
u=36.8m/s
Explanation:
because of the acceleration is a constant acceleration we can use one of the "SUVAT" equations
u^2=v^2-2ā*s. where:
u^2 stands for intial velocity
v^2 stands for final velocity
since the cougar skidded to a complete stop the final velocity is zero.
u^2=v^2-2ā*s
u^2=(0)^2 -2(-2.87 m/s^2)*236 m
u^2=0+5.74m/s^2* 236m
u^2=1354.64m^2/s^2
u=√1354.64m^2/s^2
u=36.8m/s (approximate value)
when ever the acceleration is constant you can use one of the following equation to find the required value.
1. v = u + at. (no s)
2. s= 1/2(u+v)t. (no ā)
3. s=ut + 1/2at^2. ( no v)
4. v^2=u^2 + 2āS. (no t). 5. s= vt - 1/2at^2. (no u)
Answer:
Explanation:
given,
velocity of particle 1 = 0.741 c to left
velocity of second particle = 0.543 c to right
relative velocity between the particle = ?
for the relative velocity calculation we have formula
u_x = 0.543 c
v_x = - 0.741 c
Relative velocity of the particle is
Answer:
The work done by the wind as the boat moves 130 ft is (rounded) W= 31,550 ft-lb.
Explanation:
F= 300 lb < -54º
Fsouth= 300 lb * cos(36º)
Fsouth= 242.7 lb
d= 130 ft
W= F*d
W= 31551 ft-lb
