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Anastasy [175]
3 years ago
10

80% equals 1200, then what budget is 100%?

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

$1500

Step-by-step explanation:

Let's start by converting 80% to a decimal. 80% means 80/100, or 0.8. Let's call the full budget b.

0.8b=1200

Divide both sides by 0.8 to isolate b:

b=1200/0.8=$1500

Hope this helps!

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Question 10<br> Divide £64 in the ratio 3:5
ICE Princess25 [194]

Answer:

24:40

Step-by-step explanation:

3:5

This means there are 8 divisions altogether - 8 parts to be split (3+5=8)

64 / 8 = 8

8x3 = 24

8x5 = 40

£24:£40

Hope this makes sense!

8 0
1 year ago
In a geometric sequence, the__<br> between consecutive terms is constant
kow [346]

Answer:

In a geometric sequence, the <u>ratio</u> between consecutive terms is constant.

Step-by-step explanation:

A geometric sequence is where you get from one term to another by multiplying by the same value. This value is known as the <u>constant ratio</u>, or <u>common ratio</u>. An example of a geometric sequence and it's constant ratio would be the sequence 4, 16, 64, 256, . . ., in which you find the next term by multiplying the previous term by four. 4 × 4 = 16, 16 × 4 = 64, and so on. So, in this sequence the constant <em>ratio </em>would be four.

3 0
3 years ago
Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)
NemiM [27]
Call the parabola P, parameterized by \mathbf r(y)=\langle y^2+1,y\rangle with 0\le y\le 1\rangle. Then the work done by \mathbf f(x,y) along P is

\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy
=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy
=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2
8 0
3 years ago
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5 \times  {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \bf  \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

8 0
2 years ago
Lauren had no more than $23 to spend on 5 avocados. After buying them she had $3. What is the most each avocado cost?
expeople1 [14]
23÷5=4 with a remainder of $3. each avocada was 4$.
7 0
2 years ago
Read 2 more answers
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