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3 years ago

80% equals 1200, then what budget is 100%?

Mathematics

1 answer:

dedylja [7]3 years ago

8 0

Answer:

$1500

Step-by-step explanation:

Let's start by converting 80% to a decimal. 80% means 80/100, or 0.8. Let's call the full budget b.

0.8b=1200

Divide both sides by 0.8 to isolate b:

b=1200/0.8=$1500

Hope this helps!

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Gelneren [198K]

Answer:

General equation of line : $y = mx+c$ --1

Where m is the slope or unit rate

Table 1)

p d

1 3

2 6

4 12

d = Number of dollars (i.e.y axis)

p = number of pound(i.e. x axis)

First find the slope

First calculate the slope of given points

$m = \frac{y_2-y_1}{x_2-x_1}$ ---A

$(x_1,y_1)=(1,3)$

$(x_2,y_2)=(2,6)$

Substitute values in A

$m = \frac{6-3}{2-1}$

$m = 3$

Thus the unit rate is 3 dollars per pound.

So, It matches the box 1 (Refer the attached figure)

Equation 1 : $p=3d$

$\frac{p}{3}=d$

Since p is the x coordinate and d is the y coordinate

On Comparing with 1

$m = \frac{1}{3}$

Thus the unit rate is $\frac{1}{3}$ dollars per pound

So, It matches the box 2 (Refer the attached figure)

Equation 2 : $\frac{1}{3}d=3p$

$d=9p$

Since p is the x coordinate and d is the y coordinate

On Comparing with 1

$m =9$

Thus the unit rate is 9 dollars per pound

So, It matches the box 3 (Refer the attached figure)

Table 2)

p d

1/9 1

1 9

2 18

d = Number of dollars (i.e.y axis)

p = number of pound(i.e. x axis)

$(x_1,y_1)=(\frac{1}{9},1)$

$(x_2,y_2)=(1,9)$

Substitute values in A

$m = \frac{9-1}{1-\frac{1}{9}}$

$m = \frac{8}{frac{8}{9}}$

$m = 9$

Thus the unit rate is 9 dollars per pound

So, It matches the box 3 (Refer the attached figure)

3 0

4 years ago

Read 2 more answers

Which of the following is true about the expression square root of 3 times square root of 2

dmitriy555 [2]

That it equals2.449 i did the math and that is what i got

7 0

3 years ago

While waiting for a video game to download, you notice that

salantis [7]

Find out the how many kilobytes have been downloaded so far .
To prove
As given
While waiting for a video game to download.
notice that 30 percent of 32000 kilobytes have been downloaded so far .
30% is written in the decimal form.

= 0.30
kilobytes uses in downloaded = 0.30 × 32000
= 9600 kilobytes
Therefore 9600 kilobytes have been downloaded so far .

7 0

3 years ago

How to solve this trig

n200080 [17]

Hi there!

To find the Trigonometric Equation, we have to isolate sin, cos, tan, etc. We are also given the interval [0,2π).

First Question

What we have to do is to isolate cos first.

$\displaystyle \large{ cos \theta = - \frac{1}{2} }$

Then find the reference angle. As we know cos(π/3) equals 1/2. Therefore π/3 is our reference angle.

Since we know that cos is negative in Q2 and Q3. We will be using π + (ref. angle) for Q3. and π - (ref. angle) for Q2.

Find Q2

$\displaystyle \large{ \pi - \frac{ \pi}{3} = \frac{3 \pi}{3} - \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{2 \pi}{3} }$

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{3} = \frac{3 \pi}{3} + \frac{ \pi}{3} } \\ \displaystyle \large \boxed{ \frac{4 \pi}{3} }$

Both values are apart of the interval. Hence,

$\displaystyle \large \boxed{ \theta = \frac{2 \pi}{3} , \frac{4 \pi}{3} }$

Second Question

Isolate sin(4 theta).

$\displaystyle \large{sin 4 \theta = - \frac{1}{ \sqrt{2} } }$

Rationalize the denominator.

$\displaystyle \large{sin4 \theta = - \frac{ \sqrt{2} }{2} }$

The problem here is 4 beside theta. What we are going to do is to expand the interval.

$\displaystyle \large{0 \leqslant \theta < 2 \pi}$

Multiply whole by 4.

$\displaystyle \large{0 \times 4 \leqslant \theta \times 4 < 2 \pi \times 4} \\ \displaystyle \large \boxed{0 \leqslant 4 \theta < 8 \pi}$

Then find the reference angle.

We know that sin(π/4) = √2/2. Hence π/4 is our reference angle.

sin is negative in Q3 and Q4. We use π + (ref. angle) for Q3 and 2π - (ref. angle for Q4.)

Find Q3

$\displaystyle \large{ \pi + \frac{ \pi}{4} = \frac{ 4 \pi}{4} + \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{5 \pi}{4} }$

Find Q4

$\displaystyle \large{2 \pi - \frac{ \pi}{4} = \frac{8 \pi}{4} - \frac{ \pi}{4} } \\ \displaystyle \large \boxed{ \frac{7 \pi}{4} }$

Both values are in [0,2π). However, we exceed our interval to < 8π.

We will be using these following:-

$\displaystyle \large{ \theta + 2 \pi k = \theta \: \: \: \: \: \sf{(k \: \: is \: \: integer)}}$

Hence:-

For Q3

$\displaystyle \large{ \frac{5 \pi}{4} + 2 \pi = \frac{13 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 4\pi = \frac{21 \pi}{4} } \\ \displaystyle \large{ \frac{5 \pi}{4} + 6\pi = \frac{29 \pi}{4} }$

We cannot use any further k-values (or k cannot be 4 or higher) because it'd be +8π and not in the interval.

For Q4

$\displaystyle \large{ \frac{ 7 \pi}{4} + 2 \pi = \frac{15 \pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 4 \pi = \frac{23\pi}{4} } \\ \displaystyle \large{ \frac{ 7 \pi}{4} + 6 \pi = \frac{31 \pi}{4} }$

Therefore:-

$\displaystyle \large{4 \theta = \frac{5 \pi}{4} , \frac{7 \pi}{4} , \frac{13\pi}{4} , \frac{21\pi}{4} , \frac{29\pi}{4}, \frac{15 \pi}{4} , \frac{23\pi}{4} , \frac{31\pi}{4} }$

Then we divide all these values by 4.

$\displaystyle \large \boxed{\theta = \frac{5 \pi}{16} , \frac{7 \pi}{16} , \frac{13\pi}{16} , \frac{21\pi}{16} , \frac{29\pi}{16}, \frac{15 \pi}{16} , \frac{23\pi}{16} , \frac{31\pi}{16} }$

Let me know if you have any questions!

3 0

3 years ago

Pleas help i need to get this done asap

muminat

Answer:

$160.16

Step-by-step explanation:

143 is his bill

he leaves an extra 12%

12% of 143 = 0.12 x 143 = 17.16 that's his time

143 + 17.16 = 160.16

4 0

4 years ago

Read 2 more answers