Instruments
The specific type of instruments depends on the type of laboratory that you're working in: some labs for example use electron microscopes, others use mass spectrophotometers, others use multiplex biochemical analyzers, etc. But very broadly, the specialized tools we use in the laboratory are usually referred to as "instruments"
Answer:
Coal
Explanation:
Once it's all been mined, there's no more. It's not like we grow it.
Answer:
Nassau, Bahamas
Explanation: The Bahamas are close to the equator so it has more heat which means higher water evaporation which leads to a higher humidity than the other places.
Answer:
The concentration of the solution will be much lower than 6M
Explanation:
To prepare a solution of a solid, the appropriate mass is taken and accurately weighed in a weighing balance and then made up to mark with distilled water.
From
n= CV
n = number of moles m/M( m= mass of solid, M= molar mass of compound)
C= concentration of substance
V= volume of solution
m=120g
M= 40gmol-1
V=500ml
120/40= C×500/1000
C= 120/40× 1000/500
C=6M
This solution will not be exactly 6M if the student follows the procedure outlined in the question. The actual concentration will be much less than 6M.
This is because, solutions are prepared in a standard volumetric flask. Using a 1000ml beaker, the student must have added more water than the required 500ml thereby making the actual concentration of the solution less than the expected 6M.
Answer: There are
molecules present in 183.2 grams of
gas.
Explanation:
Given: Mass = 183.2 g
Number of moles is the mass of substance divided by its molar mass.
As molar mass of water is 18 g/mol. Therefore, moles of
are calculated as follows.

According to the mole concept, there are
molecules present in one mole of a substance.
Hence, molecules present in 10.17 moles are calculated as follows.

Thus, we can conclude that there are
molecules present in 183.2 grams of
gas.