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Olin [163]
3 years ago
13

PLEASE ANSWE ASAP !!!!

Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0
It’s red I think I’m not that sure though please give brainliest
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45.83333333 as a fraction
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Answer:

275/6

Step-by-step explanation:

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28 points !!!! help
RoseWind [281]

Answer:

12 cm

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = \frac{1}{2} h (a + b)

where h is the perpendicular height and a, b the parallel bases.

Here A = 45, h = 5, a = 6 and b = ?, thus

45 = \frac{1}{2} × 5 × (6 + b) = 2.5(6 + b) = 15 + 2.5b ( subtract 15 from both sides )

30 = 2.5b ( divide both sides by 2.5 )

b = 12

The measure of the other parallel side is 12 cm

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Answer: Corresponding angles

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1 and 5 are corresponded to each other & i took the test on i-ready

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Math Exam answer!! K-12 Determine if each function is linear or nonlinear
Furkat [3]

Answer:

The screenshot shows the correct answers; 5x + 5y = 25 is linear.

For a equation to be linear:

  1. The equation should not have square root, cube root, etc.
  2. The value of x is not greater than one. X should not have an exponent.
  3. X is not in a denominator of a fraction.
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4 0
3 years ago
PLEASE BE FAST
DaniilM [7]

Here is the table of values:

Minutes   Total cost

0                 $3

1                   $3.80

2                  $4.60

3                  $5.40

The equation representing the total cost is C = $3 + $0.80tt

<h3>What is the total cost?</h3>

The total cost of using a computer is a function of the initial charge, cost per minute and total number of minutes the computer was used.

Total cost = initial charge + (cost per minute x number of minutes)

C = $3 + ($0.80 x tt)

C = $3 + $0.80tt

Total cost when the computer is used for one minute:  C = $3 +( $0.80 x 1) = $3.80

Total cost when the computer is used for two minutes:  C = $3 +( $0.80 x 2) = $4.60

Total cost when the computer is used for three minutes:  C = $3 +( $0.80 x 3) = $5.40

To learn more about total cost, please check: brainly.com/question/25717996

#SPJ1

8 0
1 year ago
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