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3 years ago

* PLEASE HELP WILL GIVE BRAINIEST* Your portfolio must include a minimum of the following five types of equations and solutions:

1 answer:

6 0

2 step equation:
4x + 3 = 19

2 step equation w/ fractions:
(4/3)x + 5 = 17

Distributive Property:
4x(6 - 2) - 10 = 20

Decimals:
4.3x + 0.7 = 5

Real world equation:
Sharon's restaurant is bringing in money from customers, and she needs to know how much she needs to pay off the bill for the electricity to run the place. To turn the electricity on, she has to pay $25. For every hour that the electricity is on for, she has to pay $4. How many hours can she have the electricity on for if she makes $49 profit?

I hope these helped! Not too sure about the last one, I sort of let me imagination run wild. In any case, don't hesitate to ask me questions if you have any further inquiries. <3

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What is the answer to 20x+7=4+6?

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You and your friends want to rent a limo on prom night. The limo costs $75 per hour plus a $50 booking fee. You have $350 to spe

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You will have the limo for 4 hours.

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Y is inversely proportional to x, when Y = 2, x = 4.<br><br>Find the value of x when Y = 4.

ratelena [41]

The value of x when y =4 is 2

<h3>How to solve for x?</h3>

An inverse proportion is represented as:

k = yx

Where

k represents the constant of proportion

When y = 2, x = 4.

So, we have:

k =2 * 4

k = 8

Substitute k = 8 in k = yx

So, we have:

yx = 8

When y = 4, we have:

4x = 8

Divide by 4

x = 2

Hence, the value of x when y =4 is 2

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brainly.com/question/14254277

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2 years ago

400 quarts into a container that holds 4/7 of a quart. how many containers were used?

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700 container
hope this helps

4 0

3 years ago

A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0

3 years ago