Answer:
hey
Your answer is E orbital.
Answer:
Back titration is a titration done in reverse; instead of titrating the original sample, a known excess of standard reagent is added to the solution, and the excess is titrated.
I hope it's helpful!
Correct answer is option D becauce C12 and C14 are isotopes.they have same atomic numbers but dif atomic masses.
M₀=100 g
T=2 s
t=8s
m=m₀/{2^(t/T)}
m=100/{2^(8/2)}=100/2⁴=6.25 g
Sulfur dioxide diffuses at one quarter the rate of helium :)