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Sliva [168]
2 years ago
10

Count the atoms 2Ca(H2PO4)3 How many O atoms are in the above equation?

Chemistry
1 answer:
Helga [31]2 years ago
7 0
I think they are 3 atoms
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What would happen if all the cordgrass was removed from the coast of South Carolina? pls help quickly
salantis [7]

Answer:

the common name cordgrass. Adaptation and Distribution Gulf cordgrass grows along the Gulf Coast from Florida to Texas, and South into Eastern Mexico. More rarely, gulf cordgrass grows inland in marshes, swamps, and moist prairies. It can also be found along the Caribbean coasts, and inland in Argentina and Paraguay.

Explanation:

Hope that helped! (can u mark brainliest?)

8 0
2 years ago
The ksp of manganese(ii) carbonate, mnco3, is 2.42 × 10-11. calculate the solubility of this compound in g/l.
Vikki [24]

Answer :  The solubility of this compound in g/L is 565.414\times 10^{-6}g/L.

Solution : Given,

K_{sp}=2.42\times 10^{-11}

Molar mass of MnCO_3 = 114.945g/mole

The balanced equilibrium reaction is,

                      MnCO_3\rightleftharpoons Mn^{2+}+CO^{2-}_3

At equilibrium                         s       s

The expression for solubility constant is,

K_{sp}=[Mn^{2+}][CO^{2-}_3]

Now put the given values in this expression, we get

2.42\times 10^{-11}=(s)(s)\\2.42\times 10^{-11}=s^2\\s=0.4919\times 10^{-5}=4.919\times 10^{-6}moles/L

The value of 's' is the molar concentration of manganese ion and carbonate ion.

Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

s=4.919\times 10^{-6}moles/L\times 114.945g/mole=565.414\times 10^{-6}g/L

Therefore, the solubility of this compound in g/L is 565.414\times 10^{-6}g/L.


8 0
3 years ago
Which two elements are combined in sodium chloride
Westkost [7]

Answer:

Sodium (Na) and Chlorine (CI)

Explanation:

6 0
3 years ago
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Each square of the periodic table shows information about one element. The square usually shows the element's
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D, all of the above.
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How much precipitation is shown in the rain gauge below?
VARVARA [1.3K]

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