Answer:
132.17 g
Explanation:
The reaction given , in the question is -
CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S ( g )
From the reaction , 4 mole of S is required for the production of 1 mole of CS₂ .
since ,
Moles of CS₂ = given mass of CS₂ / Molecular weight of CS₂
Since ,
the Molecular weight of CS₂ = 76
Given , mass of CS₂ = 72.57 g
Moles of CS₂ = 72.57 / 76 = 0.95 mol
Since ,
The yield is 92.0 % .
Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles
Mass of S required = 4.13 * 32 = 132.17 g .
I think it's 2 I tried looking it up because I was not sure.
We are asked in the problem to convert teh unit mci or millicurie to another unit of radioactivity, becquerel. The conversion to be used in this case is <span>1 millicurie [mCi] = 37,000,000 becquerel [Bq] .The problem gives 15 mCi which when multiplied to </span>37,000,000 is equal to 5,550,000,000 bQ
