Lewis structures refers to the diagrams used to signify the bonding between the atoms of a molecule and the lone pair of electrons, which may prevail in the molecule. These structures are drawn on the basis of the formal charge of each atom within the ion or molecule.
The formal charge refers to the charge assigned to an atom in a molecule, which all the electrons are shared equivalently amongst the atoms regardless of its electronegativity.
The rule for formal charge calculation is,
Formal charge = no of valency shell electron - 1/2 of the no of shared pair electron - no of lone pair electron.
So, in this case, the formal charge of P = 5 - 1/2 (10) - 0 = 0
The valence shell of P have 5 electrons. The total 5 bond is there in the given composition, so total 10 bonding electron, and there is no lone pair of electron on P atom. So, formal charge of P is 0.
Answer:
c.corn syrup
the egg shrinks due to osmosi.
Answer:
A disproportionation reaction is when a multiatomic species whose pertinent element has a specific oxidation state gets oxidized and reduced in two separate half-reactions, yielding two other products containing the same pertinent element. A convenient example is Mn2O3 becoming Mn2+ and MnO2 .
Answer:
378mL
Explanation:
The following data were obtained from the question:
Pressure (P) = 99.19 kPa
Temperature (T) = 28°C
Number of mole (n) = 0.015 mole
Volume (V) =...?
Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:
For Pressure:
101.325 KPa = 1 atm
Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm
For Temperature:
T(K) = T(°C) + 273
T(°C) = 28°C
T(K) = 28°C + 273 = 301K.
Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:
PV = nRT
Pressure (P) = 0.98 atm
Temperature (T) = 301K
Number of mole (n) = 0.015 mole
Gas constant (R) = 0.0821atm.L/Kmol.
Volume (V) =...?
0.98 x V = 0.015 x 0.0821 x 301
Divide both side by 0.98
V = (0.015 x 0.0821 x 301) /0.98
V = 0.378 L
Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:
1L = 1000mL
Therefore, 0.378L = 0.378 x 1000 = 378mL
Therefore, the volume of N2 collected is 378mL
