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Temka [501]
2 years ago
5

18) Mg and S would be expected to react in a ratio of: (1:1, 2:1, 1:2 or 2:3)

Chemistry
1 answer:
lord [1]2 years ago
8 0

Answer:

1:1.

Explanation:

Hello!

In this case, since magnesium, in the form that is able to react with sulfur, has an oxidation state of 2+ and sulfur 2-, because they need to be different in order to form a suitable compound; due to that equality in their oxidation states, we expect they react in a 1:1 mole ratio, according to the following example:

Mg+S\rightarrow MgS

Best regards!

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Calculate the standard enthalpy change for the reaction at 25 ∘C. Standard enthalpy of formation values can be found in this lis
weqwewe [10]

Answer:

\Delta H_{rxn}=-2043.999kJ

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\Delta H_{rxn}^{0}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]

Where n_{i} and n_{j} are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

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So, \Delta H_{rxn}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]

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4 0
4 years ago
PLEASE HELP!!
igomit [66]
Answer is: the specific heat capacity of the metal is <span>A) 0.129 J/gK.
</span>m(metal) = 15,1 g.
Q = 48,75 J.
ΔT = 25 K.
Q = C · ΔT · m(metal).
C = Q ÷ ΔT · m(metal).
C = 48,75 J ÷ 25 K · 15,1 g.
C = 0,129 J/g·K.
3 0
3 years ago
Read 2 more answers
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