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Vika [28.1K]
3 years ago
11

When a solid compound is formed from chemicals which are in solution, it is called a?

Chemistry
2 answers:
SVETLANKA909090 [29]3 years ago
4 0

Answer: precipitate.


Explanation:


1) When the product of the reaction between the chemicals in the solution is insoluble, then it cannot remain in the solution and it will precipiate, forming a solid substance.


2) That happens, for example, when you have two solutions with different solutes, mix them together, the solutes can react chemically with each other, yielding a product that is insoluble.


3) A typical example of such kind of precipitation reactions is athe neutralization of an acid and a base.


Acid + Base = salt + water


If the salt is insoluble in water then it will form a a precipitate (solid), if the product is soluble in water then it remains as an aqueos ions in the solution.

FromTheMoon [43]3 years ago
4 0

Answer:Answer: precipitate.

Explanation:

1) When the product of the reaction between the chemicals in the solution is insoluble, then it cannot remain in the solution and it will precipiate, forming a solid substance.

2) That happens, for example, when you have two solutions with different solutes, mix them together, the solutes can react chemically with each other, yielding a product that is insoluble.

3) A typical example of such kind of precipitation reactions is athe neutralization of an acid and a base.

Acid + Base = salt + water

If the salt is insoluble in water then it will form a a precipitate (solid), if the product is soluble in water then it remains as an aqueos ions in the solution.

Explanation:

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6. If 981 mL of a gas is heated from 335 K at constant pressure and the volume
storchak [24]

Answer:

1.5L

Explanation:

The new volume can be found by using the formula for Boyle's law which is

p1v1=p2v2

Since we are finding the new volume

v2= p1v1/p2

From the question we have

v2= 5x3/10=15/10= 3/5

We have the final answer as

1.5 L

3 0
2 years ago
We can also perform a similar calculation for the mass defect and binding energy for nuclear reactions using the masses of the a
sukhopar [10]

Answer:

See Explanation

Explanation:

\frac{235}{92} U + \frac{1}{0} n ---->\frac{137}{52} Te + \frac{97}{40} Zr +2\frac{1}{0} n

Hence the mass defect is;

[235.04393 + 1.00867] - [ 136.92532 + 96.91095 + 2(1.00867)]

=  236.0526 - 235.85361

= 0.19899 amu

Since 1 amu = 1.66 * 10^-27 Kg

0.19899 amu = 0.19899 * 1.66 * 10^-27 = 3.3 * 10^-28 Kg

Binding energy = Δmc^2

Binding energy = 3.3 * 10^-28 Kg * (3 * 10^8)^2 = 2.97 * 10^-11 J

ii) \frac{10}{5}B + \frac{1}{0}n-----> \frac{7}{3} Li + \frac{4}{2} He + Energy

Hence the mass defect is;

[10.01294 + 1.00867] - [7.01600 + 4.00260]

= 11.02161 - 11.0186

= 0.00301 amu

Since 1 amu = 1.66 * 10^-27 Kg

0.00301 amu = 0.00301 * 1.66 * 10^-27 = 4.997 * 10^-30 Kg

Binding energy = Δmc^2

Binding energy = 4.997 * 10^-30 Kg * (3 * 10^8)^2 = 4.5 * 10^-13 J

7 0
2 years ago
What is the freezing point of an aqueous 1.58 molal nacl solution?
Alina [70]
<span>Tf is the freezing point of the solution(the solvent plus solute). T*f is the freezing point of the pure solvent(without solute) i is the van't Hoff factor.It is approximately the number of particles in solution that are made for each particle of the solute that is placed into solution.Therefore, for nonelectrolytes, i = 1. Kf is the freezing point depression constant.For water, Kf = 1.86 Degree C/m, or 1.86 Degree C.kg/mol. Tf is -1.58 Degree C</span>
4 0
3 years ago
2. How much heat must be absorbed by a sample of 1337 grams (g) of ice at -10°C in order to turn it into water vapor at 120°C?​
olya-2409 [2.1K]

Answer:

jk

Explanation:

3 0
3 years ago
The first-order rate constant for the decomposition of n2o5, 2n2o5(g)→4no2(g)+o2(g) at 70∘c is 6.82×10−3 s−1. suppose we start w
torisob [31]

The rate constant for 1st order reaction is

K = (2.303 /t) log (A0 /A)

Where, k is rate constant

t is time in sec

A0 is initial concentration

(6.82 * 10-3) * 240 = log (0.02 /A)

1.63 = log (0.02 /A)

-1.69 – log A = 1.63

Log A = - 0.069

A = 0.82

Hence, 0.82 mol of A remain after 4 minutes.

7 0
3 years ago
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