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Vika [28.1K]
3 years ago
11

When a solid compound is formed from chemicals which are in solution, it is called a?

Chemistry
2 answers:
SVETLANKA909090 [29]3 years ago
4 0

Answer: precipitate.


Explanation:


1) When the product of the reaction between the chemicals in the solution is insoluble, then it cannot remain in the solution and it will precipiate, forming a solid substance.


2) That happens, for example, when you have two solutions with different solutes, mix them together, the solutes can react chemically with each other, yielding a product that is insoluble.


3) A typical example of such kind of precipitation reactions is athe neutralization of an acid and a base.


Acid + Base = salt + water


If the salt is insoluble in water then it will form a a precipitate (solid), if the product is soluble in water then it remains as an aqueos ions in the solution.

FromTheMoon [43]3 years ago
4 0

Answer:Answer: precipitate.

Explanation:

1) When the product of the reaction between the chemicals in the solution is insoluble, then it cannot remain in the solution and it will precipiate, forming a solid substance.

2) That happens, for example, when you have two solutions with different solutes, mix them together, the solutes can react chemically with each other, yielding a product that is insoluble.

3) A typical example of such kind of precipitation reactions is athe neutralization of an acid and a base.

Acid + Base = salt + water

If the salt is insoluble in water then it will form a a precipitate (solid), if the product is soluble in water then it remains as an aqueos ions in the solution.

Explanation:

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             Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,

                         Molarity  =  Moles / Volume of Solution    ----- (1)

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                         Volume of solution  =  Moles / Molarity    -------(2)

Data Given;

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First calculate Moles for given mass as,

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Now, putting value of Moles and Molarity in eq. 2,

                         Volume of solution  =  0.0130 mol / 0.00813 mol.L⁻¹

                         Volume of solution  = 1.60 L

or,

                         Volume of solution  =  1602 mL

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