Answer: Height of building = 17.69m, velocity of brick = 18.6m/s
Explanation: From the question, the body has a zero initial speed, thus initial velocity (u) all through the motion is zero.
By ignoring air resistance makes it a free fall motion thus making it to accelerate constantly with a value of 
.
Time taken to fall = 1.90s
a)
thus the height of the building is calculated using the formulae below
but u = 0 , hence
b)
to get the value of velocity (v) as the brick hits the ground, we use the formulae below
but u= 0, hence
find the attachment in this answer for the accleration- time graph, velocity- time graph and distance time graph
Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
= 
ε₀cE
²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E )
E = 350/f kV/m
given that frequency of 60 Hz, we substitute
E = 350/60 kV/m
E = 5.83333 kV/m
E = 5.83333 kV/m × ( 
)
E = 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
= ε₀cE²
= × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
= 45 × 10³ W/m²
= 45 × 10³ W/m² × ( 
)
= 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
The movement of water molecules from higher to lower concentration is osmosis.
For one thing, hydrogen gas or fuel is really expensive compared to present diesel and gasoline. There's no point in actually investing in them since economy will not improve otherwise. Gasoline stations will also have to adjust to how tricky hydrogen gas will be to support and store with ease. It's dangerous also to the driver, passengers and our environment.
Answer:
a) 0.99999 e
b) 1*10^-5 s
c) 3*10^-2 m
Explanation:
Given data:
Electron energy : 50 GeV
assuming the rest mass of an electron = 0.5 MeV/c^2
A) Determine the velocity of each electron
velocity of each electron ( v ) ≈ 0.999 e
B) How much time does it take the electrons to travel the length of the accelerator given that the accelerator = 3km long
Lo = 3 * 10^3 m
T = (3 * 10^3 )/ (0.999 * 3 * 10^8)
= 1 * 10 ^-5
C) How long does the accelerator look form the perspective of the electrons
L = Lo / r = Lo 
hence L = 3 * 10^-2 m
