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Annette [7]
3 years ago
14

What law allows calories to be determined by heat (energy) transfer from one substance to another, but it is never destroyed?

Chemistry
1 answer:
Mila [183]3 years ago
6 0

Answer:

matter i think

Explanation:

matter i am pretty sure

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Here is the information: A 1.2516 gram sample of a mixture of CaCO3 and Na2SO4 was analyzed by dissolving the sample and adding
tiny-mole [99]

Answer:

93,32 % (w/w)

Explanation:

The Ca²⁺ of CaCO₃ was completely precipitate to CaC₂O₄ that results in H₂C₂O₄. The titration of this one is:

3H₂C₂O₄ + 2H⁺ + MnO₄⁻ → Mn²⁺ + 4H₂O + 6CO₂

As you required 35,62mL of 0,1092M MnO₄⁻, the moles of H₂C₂O₄ are:

0,03562L×\frac{0,1092M}{L} =

3,890x10⁻³mol of MnO₄⁻×\frac{3molH_{2}C_{2}O_{4}}{1mol MnO_{4}^-} = <em>0,01167 mol of H₂C₂O₄</em>

The number of moles of CaCO₃ are the same number of moles of H₂C₂O₄ because every Ca²⁺ was converted in CaC₂O₄ that was converted in H₂C₂O₄. That means: <em>0,01167 mol of CaCO₃</em>

0,01167 mol of CaCO₃ are:

0,01167 mol of CaCO₃×\frac{100,0869g}{1mol} = <em>1,168 g of CaCO₃</em>

As the mass of the initial mixture is 1,2516 g, the percentage by weight of CaCO₃ is:

\frac{1,168g}{1,2516g}×100 = <em>93,32 % (w/w)</em>

I hope it helps!

7 0
3 years ago
What type of bond would be found between
LenaWriter [7]

Answer:

  1. covalent bond
  2. polar covalent bond
  3. ionic bond
  4. metallic bond

Explanation:

<h2>hope it helps you </h2><h2>.</h2><h2>.</h2><h2>.</h2><h2>.</h2><h2>.</h2><h2>.</h2><h2>Thank uu</h2>
3 0
3 years ago
Balance the following chemical equation: CH4+ Cl2 → CCl4+ HCI​
inn [45]

Explanation:

CH4+8/2Cl2—>CCl4+4HCl

that is,1molecule of methane+8/2 molecules of dichlorine—>1molecule of carbon tetrachloride+4molecules of hydrogen chloride

5 0
2 years ago
Match the average rates of change of fx) to the corresponding intervals.
Musya8 [376]
Do you still need help?!?!?
6 0
3 years ago
PLEASE HELP!
Andrei [34K]
We will first calculate the concentration of sodium hydroxide, knowing the massive K hp. That was required to neutralize the 22.65 ml of sodium hydroxide solution. So the polarity sodium hydroxide will be take the massive K HP divided by its molar mass to get moles K HP. Then recognize one mol K HP reacted with one mole sodium hydroxide. Now we have mold sodium hydroxide to get concentration. We simply multiply by the leader volume of the sodium hydroxide solution. 22.65 ml is .02265 L. And we get a polarity of zero 0.3351 Molar sodium hydroxide. Now to calculate the concentration of hcl, we need to know the molds hcl divided by the volume of the hcl solution. To get the moles. Hcl will take the 25 ml of sodium hydroxide used in the tight rations converted to leaders. 25 ml is .02500 l multiply that by the concentration of sodium hydroxide that we just determined up here to get mold sodium hydroxide, then convert moles sodium hydroxide into molds. Hcl, recognizing it's a 1 to 1 molar relationship. Now that we have moles hcl, we just divide by the leaders of the hcl solution that was titrate, id 0.2. Sorry, 23.35 mL is 0.2335 liters. And we get a concentration of 0.3588 molar hcl. I hope that helps
7 0
2 years ago
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