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Taya2010 [7]
3 years ago
15

I was wondering what these lines mean? and if so can you guys help me calculate the perimeter of the rhombus?

Mathematics
1 answer:
Vesna [10]3 years ago
3 0
The lines mean that they are congruent! so the perimeter is 25*4 = 100
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What is the volume of the oblique cube
serious [3.7K]

Answer:

\large\boxed{V=\dfrac{1600\pi}{3}\ cm^3}

Step-by-step explanation:

The formula of a volume of a cone:

V=\dfrac{1}{3}\pi r^2H

r - radius

H - height

We have r = 10cm and H = 16cm. Substitute:

V=\dfrac{1}{3}\pi(10^2)(16)=\dfrac{1}{3}\pi(100)(16)=\dfrac{1600\pi}{3}\ cm^3

6 0
3 years ago
Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more
Llana [10]

Given :

Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more tickets were sold to students than to teachers. 904 tickets were sold to parents.

To Find :

How many tickets were sold to students.

Solution :

Ticket sold to teachers, T = 563 .

Ticket sold to parents, P = 904 .

Let, ticket sold to students are S.

Now, it is given that :

S = T + 904

S = 563 + 904

S = 1467  students

Therefore, tickets sold to students are 1467 .

Hence, this is the required solution.

6 0
3 years ago
Please help me with this question
iris [78.8K]
A= \pi r^2  \ \ \ and \ \ \ C=2 \pi r \ \ \ \ \to \\  \\  \cfrac{\pi r^2 }{2 \pi r}= \cfrac{22}{1}    \ \  \ \ \to \ \ \ \ \    \cfrac{ r }{ 2}= \cfrac{22}{1} \ \  \ \ \to \ \ \ \ \ r=22*2=44 \ cm \\  \\  \\  C=2 \pi r=2*3.14*44=276.32  \ cm

Answer is 276.32 cm
6 0
3 years ago
Find the surface area of the composite figure. 6cm 5 cm 20cm 4cm 12cm 6cm​
Crazy boy [7]

Answer:

644 cm²

Step-by-step explanation:

Surface area of the composite figure = surface area of the large rectangular prism + surface area of the small rectangular prism - 2(area of the surface of the small rectangular prism that joins the larger prism)

✔️Surface area of the large rectangular prism = 2(LW + LH + WH)

L = 6 cm

W = 5 cm

H = 20 cm

Surface area = 2(6*5 + 6*20 + 5*20)

= 500 cm²

✔️Surface area of the small rectangular prism = 2(LW + LH + WH)

L = 6 cm

W = 4 cm

H = 12 cm

Surface area = 2(6*4 + 6*12 + 4*12)

= 288 cm²

✔️area of the surface of the small rectangular prism that joins the larger prism = L*W

L = 12 cm

W = 6 cm

Area = 12*6

= 72 cm²

✅Surface area of the composite figure = 500 + 288 - 2(72)

= 644 cm²

7 0
3 years ago
The equation for line r can be written as y=-1/4x+3. Line s which is parallel to lone r includes the point (-4,3). What is the e
MaRussiya [10]

Answer:

y=-\frac{1}{4}x+2

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form:y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)
  • Parallel lines always have the same slope

<u>1) Determine the slope of line S using line R (m)</u>

y=-\frac{1}{4} x+3

We can identify clearly that the slope of the line is -\frac{1}{4}, as it is in the place of m. Because parallel lines always have the same slope, the slope of line S would also be -\frac{1}{4}. Plug this into y=mx+b:

y=-\frac{1}{4}x+b

<u>2) Determine the y-intercept of line S (b)</u>

y=-\frac{1}{4}x+b

Plug in the given point (-4,3) and solve for b

3=-\frac{1}{4}(-4)+b\\3=1+b

Subtract 1 from both sides to isolate b

3-1=1+b-1\\2=b

Therefore, the y-intercept is 2. Plug this back into y=-\frac{1}{4}x+b:

y=-\frac{1}{4}x+2

I hope this helps!

6 0
2 years ago
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