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yKpoI14uk [10]
2 years ago
9

Una funzione inversamente proporzionale è rappresentata da?

Mathematics
1 answer:
puteri [66]2 years ago
3 0
Supponiamo che due variabili x e y siano inversamente proporzionali; allora possiamo rappresentarli come x ∝ 1 / y. Ciò significa che se il valore di x aumenta, il valore di y diminuisce e viceversa.


Suppose two variables x and y are inversely proportional; then we can represent them as x ∝ 1/y. That means, if the value of x increases, then the value of y decreases and vice versa.

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I need helpppp, I need to turn this in before class is over
svetoff [14.1K]

Answer:

.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the additive inverse of 7/10
11111nata11111 [884]

\huge\fbox{Hi~there!}

Remember, a number's additive inverse is simply its opposite.

Let's say we have a number a.

The opposite of a is -a, and the opposite of -a is a.

Thus, the additive inverse of

\displaystyle\frac{7}{10} is

\displaystyle-\frac{7}{10}

Hope it helps.

~Just a felicitous girl

#HaveAnAmazingDay

Feel free to ask if you have any doubts.

\bf{-MistySparkles^**^*

5 0
2 years ago
Describe the translation of the function from the parent function f(x) = x².
kkurt [141]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\

\end{array}\\

\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}


now, notice the template above... now let's see your function \bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}

so.. what do you think was the shift then?
8 0
3 years ago
Solve the equation. 33 = p – 6.71<br> A. –39.71 <br> B. –26.29 <br> C. 39.71 <br> D. 26.29
jeka57 [31]

<u>Answer</u>

C. 39.71


<u>Explanation</u>

33 = p - 6.71

The first step is to make the like terms to be on the same side.

Add 6.71 on both sides of the eqution

33 +  6.71 = p - 6.71 + 6.71

39.71 = p


∴ p = 39.71

4 0
2 years ago
What is the measure of the largest angle of a triangle whose measures are in the ratio 2:3:4
malfutka [58]
2x+3x+4x=180
9x=180
x=20
6 0
3 years ago
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