Answer:
3.88m/s
Explanation:
Using the law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and 2 are the initial velocities
v is the final velocity
Given
m1 = 64kg
u1 = 4.2m/s
m2 = 25kg
u2 = 3.2m/s
Required
Final velocity v
Substitute the given values into the formula
64(4.2)+25(3.2) = (65+25)v
268.8+80 = 90v
348.8 = 90v
v = 348.8/90
v = 3.88m/s
Hence the velocity of the kayak after the swimmer jumps off is 3.88m/s
Answer:
Natalie says that all things with mass have a gravitational field, but the force is very weak and cannot be perceived around small objects.
Explanation:
The force due to gravity is proportional to the mass of the object and inversely proportional to the square of the distance between objects. The Earth is so massive that the force due to its gravity is much greater than the force between objects on the counter.
If there were no friction, the objects might move toward each other, depending on what other masses were near them tending to cause them to move in other directions.
Natalie's explanation is about the best.
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<em>Additional comment</em>
The universal gravitational constant was determined by Henry Cavendish in the late 18th century using lead balls weighing 1.6 pounds and 348 pounds. His experiment was enclosed in a large wooden box to minimize outside effects. While these masses are somewhat greater than those of a glue bottle and stapler, the experiment shows the force of gravity between "small" objects <em>can</em> be measured.
Let at any instant of time the speed is vo and the angle made by the bike with the horizontal is given
now we have
component of speed in x direction given as

component of speed in y direction will be

now from above two equations we can say that here
= angle with the horizontal at any instant
and since here it is a sine curve so we know that

so we have slope of graph

It’s true all the way. It’s true
Answer:
10.15Ω
Explanation:
From ohm's law,
V = IR...................... Equation 1
Where V = Voltage, I = current, R = resistance.
Assume the voltage across the resistance = V,
Given: I = 6.3 A
Substitute into equation 1
V = 6.3R.................. Equation 2
When an additional resistance of 3.4 Ω is inserted in series with R,
The voltage remain the same, but the current changes
Total Resistance(Rt) = (R+3.4)Ω, I' = 4.72 A
Also from ohm' law,
V = I'Rt............... Equation 3
Substitute the value of I' and Rt into equation 3
V = 4.72(R+3.4)............... Equation 5.
Divide equation 2 by equation 5
V/V = 6.3R/4.72(R+3.4)
1 = 1.335R/(R+3.4)
1 = 1.335R/(R+3.4)
R+3.4 = 1.335R
3.4 = 1.335R-R
3.4 = 0.335R
R = 3.4/0.335
R = 10.15Ω