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3 years ago

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A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink. A player applies a horizonta

l force to the puck which causes it to travel 1.25 meters in 5 seconds. What net force is exerted on the puck?

1 answer:

Leya [2.2K]3 years ago

6 0

Hello!

$\large\boxed{0.018 N}$

Begin by finding the acceleration of the puck. Use the kinematic equation:

$d = v_{i} + \frac{1}{2}at^{2}$

The initial velocity is 0 m/s since the object was at rest, so we can rewrite the equation as:

$d = \frac{1}{2}at^{2}$

Plug in the given distance and time:

$1.25 = \frac{1}{2}a(5^{2})\\\\2.50 = 25a\\\\a = 0.1 m/s^{2}$

Find the net force using the formula F = m · a (Newton's Second Law)

F = 0.18 · 0.1

F = 0.018 N

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